The answer cannot be determined. To answer the question, assuming identical height boxes, we need to know the height of a box.
6
That would be 4300 inches -about a s high as a 35 story building
20 foot containers are generally 8 feet wide and 8.5 feet high. Taking that as the dimensions, you have 96 inches x 102 inches x 240 inches. 240/24 means 10 boxes can fit lengthwise. 96/18 and 102/18 mean you could fit 5 boxes wide and 5 boxes high, for a total of 5x5x10 = 250 boxes. You could also fit 4 boxes placing them lengthwise across the width (96/24). That would still stack 5 high, and then 240/18 = 13 boxes lengthwise. 4x5x13 = 260 boxes, so you could fit 10 more by stacking them that way.
The answer depends on how many boxes in each layer. And since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
A one-inch stack would contain about 233 bills.
none its a werehouse
It depends on how many dollar bills you have! Lacking that variable, one US dollar is 0.0043 inches thick. So, a stack of one million dollars is about 358 feet four inches high.
12 boxes, if you do not stack the boxes.
There are 1302 of them.
Roughly 325
825,305 of them.
100 \
Six inches
Historically a stack of paper would be up to the ceiling - so how high is the ceiling?
870; a quarter has a thickness of about 0.07 inches, and 61 / 0.07 = 870.
A stack of 1303 nickels.
A can of your standard pop or beer is 4.8125 inches tall. A mile is 5,280 feet high and multiply that by 12 and you find that a mile is 63,360 inches high. 63,360 (inches in a mile) divided by 4.8125 (one can height) equals 13,166 cans needed to make a stack of cans a little over one mile high.