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Who many angles does a Irregular polygon have?
an irregular polygon is a polygon that is the opposite of a regular polygon in a regular polygon the sides are the same and the angles are the same and irregular is the opposite.
What polygon has 5040 interior angles?
A polygon with 5040 interior angles has 5041 sides. The formula for the number of interior angles in a polygon is given by ( n ), where ( n ) is the number of sides. Since each polygon has as many interior angles as it has sides, a polygon with 5040 interior angles must have 5041 sides.
How many sides does a polygon have with angles of 12 degrees?
Any polygon can have two interior angles of 12 degrees. No polygon can have all its interior angles of 12 degrees.
How many extrerior angles does a polygon have?
As many as it has interior angles. The exact amount depends on the specific polygon.
How many sides does a 24 degrees polygon have?
It cannot be a regular polygon with interior angles of 24 degrees since the smallest interior angle in a regular polygon is 60 degrees. If it is an irregular polygon, then any one of them, with 3 or more sides, can have an angle of 24 degrees.
How many side does a regular polygon have with an interior angle of 30?
The smallest regular polygon, an equilateral triangle, has interior angles of 60. A square has interior angles of 90. There can't exist a regular polygon with interior angles of 30.
How many sides does a polygon have if the interior angles equal 180 degrees?
If all of the interior angles of the polygon add up to 180 degrees, then the polygon is a triangle.
How many sides does a polygon have if one of the interior angles is 30 degrees?
No such regular polygon exist so it has to be some kind of irregular polygon but if each exterior angle was 30 degrees then it would be a regular 12 sided polygon
How many sides does an irregular polygon have when its interior angles add up to 5040 degrees showing work?
It is: (5040+360)/180 = 30 sides
How many interior angles does a many sided polygon have?
(number of sides -2)*180 = sum of interior angles
How many sides does a polygon have if the interior angles equal 1260?
Sum of interior angles of a polygon = (2n - 4)right angles 1260 = (2n - 4) x 90 1260 = 180n - 360 900 = 180n n = 5, it is a pentagon
If the sum of the interior angles of a polygon is 900 how many sides does the polygon have?
7
