1 joule = 2.39 X 10-4 kcal
65-30 = 35 degrees
1 kcal = 1 degree kg
35 degrees X 0.5 kg / 2.39 X 10-4 kcal/joulle = 73222 joules
q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============
E = mass x specific heat x Δ°T Δ°T = new temperature - original temperature where Δ°T is equal to temperature change (Celsius in this case). The specific heat of Al is 0.900 J/g°C. Before we proceed to find the quantity of heat in joules, we must first find the temperature change. To calculate the temperature change, we must subtract the original temperature from the new temperature. Δ°T = 50°C - 25°C = 25°C In order to find the quantity of heat (joules), we must multiply mass, specific heat, and the temperature change (calculated above). E = 40.0g x 0.900 J/g°C x 25°C = 900 Joules or 9.0 x 102 Joules
The energy required to raise the temperature of water depends on the atmospheric pressure as well as the starting temperature. At a pressure of one atmosphere, the amount of energy required to raise the temperature of water from 0 deg C to 100 deg C (32 to 212 deg F) is 4.19 joules per gram. At 4 deg C, (39.2 deg F) it is approx 4.204 joules per gram per deg C. That is 4.204/1.8 = 2.33555... recurring joules per gram per deg F and so, for a kilogram, the energy required is 2335.55... joules.
Heat energy is measured in joules (newton-meters), which are also a unit of work.The calorie is a mostly-superseded unit equal to 4.2 joules, while the "food energy" calorie is actually a kilocalorie (1000 calories).Units of temperature are a related value, indicating the relative contained heat energy. The units of temperature are the kelvin / degree Celsius and the different interval, the degree Fahrenheit. Classically, adding 1 mean calorie of heat energy would raise the temperature of 1 gram of water by 1 degree Celsius.
The specific heat of air at 0 degrees Celsius is 1.01 Joules per gram or J/g. The specific heat of a substance is defined as the quantity of heat per unit mass needed to raise its temperature by one degree Celsius.
q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============
15.37684 joules
About 322.5 Joules of heat
Q = 3 000 . 0,444 . ΔT (joules)ΔT is the difference of temperature.
It takes 4186 joules to raise the temperature of 1 kilogram of water by 1 degree Celsius. The mass does make a difference.
15480.80
specific heat(; your welcome!
specific heat(; your welcome!
4.184 J/g/K = 4.184 x 150 x (318-274) = 27614 Joules
specific heat is the amount of heat to be absorbed required to raise a substance 1 degree celsius. And by heat being absorbed, i mean energy, because specific heat is measured in joules
we use a match to raise the temperature of the alcohol that the wick absorbed
The answer is 53,683 kJ.