0
How many joules are absorbed by the water with a mass of 8 kg in order to raise the temperature from 20 degrees to 70 degrees?
Wiki User
∙ 10y ago
q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams )
q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C)
= 1.7 X 106 joules
============
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
How many joules are absorbed by the water with a mass of 0.5 kg in order to raise the temperature from 30 to 65?
1 joule = 2.39 X 10-4 kcal 65-30 = 35 degrees 1 kcal = 1 degree kg 35 degrees X 0.5 kg / 2.39 X 10-4 kcal/joulle = 73222 joules
What is the quantity of heat in joules needed to raise the temperature of 40.0g of Al from 25 degrees Celsius to 50 degrees Celsius?
E = mass x specific heat x Δ°T Δ°T = new temperature - original temperature where Δ°T is equal to temperature change (Celsius in this case). The specific heat of Al is 0.900 J/g°C. Before we proceed to find the quantity of heat in joules, we must first find the temperature change. To calculate the temperature change, we must subtract the original temperature from the new temperature. Δ°T = 50°C - 25°C = 25°C In order to find the quantity of heat (joules), we must multiply mass, specific heat, and the temperature change (calculated above). E = 40.0g x 0.900 J/g°C x 25°C = 900 Joules or 9.0 x 102 Joules
What temperature in degrees Fahrenheit would a fixed volume of gas need to be heated to in order to double its pressure if it starts out at 25 degrees Fahrenheit?
58 F
How do you calculate a temperature increase from minus 15 to 45 degrees?
In order to walk from 15 below ground to 45 above ground, you have to climb a total of 60 floors.
A 1.50Kg iron horseshoe initially at 600 degrees C is dropped into a bucket containing 20.0Kg of water at 25.0 degrees C What is the final temperature?
You need the heat capacities for these substances in order to answer this question. If you have those, it's simple algebra.
How many joules are absorbed by the water with a mass of 0.5 kg in order to raise the temperature from 30 to 65?
1 joule = 2.39 X 10-4 kcal 65-30 = 35 degrees 1 kcal = 1 degree kg 35 degrees X 0.5 kg / 2.39 X 10-4 kcal/joulle = 73222 joules
What is the quantity of heat in joules needed to raise the temperature of 40.0g of Al from 25 degrees Celsius to 50 degrees Celsius?
E = mass x specific heat x Δ°T Δ°T = new temperature - original temperature where Δ°T is equal to temperature change (Celsius in this case). The specific heat of Al is 0.900 J/g°C. Before we proceed to find the quantity of heat in joules, we must first find the temperature change. To calculate the temperature change, we must subtract the original temperature from the new temperature. Δ°T = 50°C - 25°C = 25°C In order to find the quantity of heat (joules), we must multiply mass, specific heat, and the temperature change (calculated above). E = 40.0g x 0.900 J/g°C x 25°C = 900 Joules or 9.0 x 102 Joules
Can it ever snow at 60 degrees Fahrenheit?
In order for snow to occur, the ground temperature must be a temperature of 32 degrees or lower.
How many joules of heat are requied to melt 40 g of ice at 0 C?
In order to answer this question, you need the enthalpy of fusion of ice, which is 333.55 J/g (Joules/gram). The enthalpy of fusion is the amount of heat that must be absorbed or lost in order to change physical state. The number of Joules required to melt the ice = enthalpy of fusion of ice x mass of ice. Joules needed to melt the ice = 333.55 J/g x 40 g = 13342 J
How many grams of water could be heated from 25 degrees Celsius to 100 degrees Celsius upon absorption of 4.22 kcal of heat?
E = mass x specific heat x Δ°t (temperature change)------------------ Energyspecific heat * temperature change = massΔ°t = new temperature - original temperatureIn order to calculate the mass of water able to be heated, we must divide the given energy by the result of specific heat times temperature change. Before proceeding to do such, we must calculate the temperature change, as well as convert cal to joules. It is also important to know that water's specific heat is 4.184 J/g°C.1. Calculate temperature change.Δ°t = 100°C-25°CΔ°t= 75°C2. Convert kcal to joules (multiply kcal * 103 * 4.184 joules [J]). (kcal --> joules)Joules = 4.22 kcal x 103 cal x 4.184 J/g°C = 17656.48 Joules------------------------ 1 kcal ------ 1 cal3. Find mass.Mass = 17656.48J(4.184J/g°C * 75°C) = 56.3g
What is the order of Fahrenheit?
Fahrenheit is a temperature scale in which water freezes at 32 degrees and boils at 212 degrees
What temperature should water be in order to disinfect?
82 degrees C !!!
What is the final temperature if 4.00 x 104 joules of energy are removed from 500.0g H2O at 10.0 degrees Celsius?
E = mass x sp ht x Δ°tIn order to calculate the final temperature change, we must also find the temperature change.1. Find the temperature change.Divide joules by (mass x specific heat).Δ°t = 40,000J/500.0g x 4.184J/g°CΔ°t = 19.1°C2. Calculate the final temperature.Tf = 10.0 - 19.1Tf = -9.1°CThere was a decrease in temperature, indicating that it was an endothermic reaction (as energy was removed as stated in the question).
How high in temperature does water have to reach in order to reach boiling point?
In order for water to reach it's boiling point, then the temperature has to reach 212 degrees. 212 degrees is for about sea level. it will vary depending on where you are.
What temperature does the NHL keep hockey pucks?
According to the NHL, the ice is supposed to remain between 20 and 22 degrees Fahrenheit; with 22 degrees being the optimal ice temperature. The temperature inside the arena itself is supposed to remain below 65 degrees.
How many joules of heat are required to melt 40 kg of ice at 0 dg C?
In order to answer this question, you need the enthalpy of fusion of ice, which is 333.55 J/g (Joules/gram). The enthalpy of fusion is the amount of heat that must be absorbed or lost in order to change physical state. The number of Joules required to melt the ice = enthalpy of fusion of ice x mass of ice. 1 kg = 1000g 40kg x (1000g/1kg) = 40,000g Joules needed to melt the ice = 333.55 J/g x 40000 g = 13342000 J or 1.3342 x 107 J
What are the energy formulas involving specific heat mass and temperature change?
E = mass x sp ht x Δ°t (Finding Energy)where E (Energy) or Q (Quantity of Heat), mass (g), sp ht (aka specific heat, J/g°C*[typical] or cal/g°C or kcal/g°C), and Δ°t (temperature change). Finding Temperature ChangeDivide energy by mass multiplied by specific heat. Δ°t = Energy-- Mass * sp htIn order to find the final temperature (if problem is asking for this), add or subtract the original temperature and the new temperature together.Tf = original temperature +/- new temperatureIf energy is added, the temperatures will be added together; if energy is removed, the temperatures will be subtracted.Finding MassDivide energy by specific heat multiplied by temperature change. Mass = Energy------- sp ht * Δ°tFinding Specific HeatDivide energy by mass multiplied by temperature change. Sp ht = Energy------- Mass * Δ°tConverting Form of Energy (joules, kcal, and cal)Sometimes a problem will have E be shown in cal/g°C or kcal/g°C but will be asking for Joules or even vice versa. This means a conversion has to take place. Cal --> Joules and Joules --> cal-Calories (Cal) --> Joules (J)Multiply # cal by 4.184 Joules (J).Conversion Factor# cal x 4.184 J = Joules---------- 1 cal1 cal = 4.184 Joules-Joules (J) --> Calories (Cal)Divide # Joules (J) by 4.184Conversion Factor# J x 1 cal = cal--- 4.184 J1 Joule = 0.239005736 calKcal --> Joules (J) and Joules (J) --> Kcal-Joules --> kcal (Joules --> cal --> kcal)Divide # J by # kcal multiplied by 103Conversion Factor# Joules x 1 cal - * - 1kcal = kcal---------- 4.184J -- 103 cal1 kcal = 4,184 Joules 1 Joule = 0.000239005736 kcal-Kcal --> Joules (J) (Kcal --> cal --> Joules)Multiply # kcal by 103 cal by 4.184JConversion Factor# kcal * 103 cal * 4.184J = Joules (J)----------- 1 kcal --- 1 calAnother relationship that is good to understand: 1 kcal = 1000 (103) cal 1 cal = 0.001 (10-3) kcal
