Short answer: 2kcal
To be preceise, it depends on the temperature of the water, because the heat capacity of a substance changes with temperature. But in a practical sense, that doesn't matter, because the change is usually very small.
If we know the definition of a calorie, it's actually quite easy to calculate this. 1 calorie is the amount of energy required to increase the temperature of 1g of water by 1C. What we need to do is just play with the definition so that it fits with our numbers. So to raise 100g of water with 20C, we need 1cal*C-1*g-1*100g*20C = 2000 cal = 2 kcal (1 kcal = 1 kilocalorie = 1000 cal)
2500 ml's
1 cal is the energy used to heat 1 g of water by 1K
E = mass x specific heat x Δ°t (temperature change)------------------ Energyspecific heat * temperature change = massΔ°t = new temperature - original temperatureIn order to calculate the mass of water able to be heated, we must divide the given energy by the result of specific heat times temperature change. Before proceeding to do such, we must calculate the temperature change, as well as convert cal to joules. It is also important to know that water's specific heat is 4.184 J/g°C.1. Calculate temperature change.Δ°t = 100°C-25°CΔ°t= 75°C2. Convert kcal to joules (multiply kcal * 103 * 4.184 joules [J]). (kcal --> joules)Joules = 4.22 kcal x 103 cal x 4.184 J/g°C = 17656.48 Joules------------------------ 1 kcal ------ 1 cal3. Find mass.Mass = 17656.48J(4.184J/g°C * 75°C) = 56.3g
Fats: 9.3 kcal/gm Glucose/ carbohydrates: 4.2 kcal/gm Proteins: 5 kcal/gm
It depends a little on what temperature it is to start with.The heat capacity of water is 4.184 J g–1 K–1 (which in calories is equal to 1 cal g–1 K–1), which means that it takes a little more than 4 Joules to heat 1 gram of water 1 °C. That means if the water is at room temperature (25 °C) you have to raise the temperature by 75 °C to reach the boiling point.So 1 lb of water is is 453.59 grams, so that gives 1898.5 Joules (1.898 kJ) or 7943.3 calories (7.943 kcal) to heat 1 pound of water 75°C.But that's just to get it to the boiling point. You then need more energy to convert the liquid water at 100 °C into gaseous water at 100 °C, and for that you need something called the heat of vaporization. For water that is 2258 J g-1(or 539.7 cal g-1).So, multiplying by 453.59 g/lb, we get 1,024,357 J lb-1 (or 1024 kJ/lb), or 244.83 kcal per lb.So most of the energy goes into turning water at 100 °C into steam at 100 °C, and so the answer is approximately 1025 kJ per pound, or 250 kcal per pound.
This is the abbreviation for kilocalorie, the metric name for one thousand calories. thus, 1.0 kcal = 1,000 cal Kilocalorie is the amount of heat energy require to raise 1 kilo or 2.2 pounds of water one degree Celsius ( centigrade ). Similarly, a calorie is the amount of heat energy required to raise one cubic centimetre of water one degree.
If a person consumes 2500 kcal a day this would require them to take in 344 grams of carbohydrates. This amount of carbohydrates is necessary to burn this level of kcals in the body.
760 kcal/ton clinker
1950 grams
50 grams of raw spinach has 11.5 kcal.
Fat = 9 kcal 2,200 kcal x 0.30 kcal = 660 kcal 660 / 9 kcal = 73.33 g = 73 g of fat per day
825 kcal
96 kcal per 100 grams of krill
A calorie is the amount of energy that needed to raise the temperature of one gram of water one degree Celsius. The Joule is the SI unit for energy.
1 joule = 2.39 X 10-4 kcal 65-30 = 35 degrees 1 kcal = 1 degree kg 35 degrees X 0.5 kg / 2.39 X 10-4 kcal/joulle = 73222 joules
There are 171.04 kcal in 100 grams of boiled chicken.
Assuming 4 kcal/g for carb and protein and 9 kcal/g for fats, the total would be (15 x 9) + (25 x 4) + (20 x 4) = 315 kcal.