222.223 ml @ 20% solution = 44.444 ml
277.777 ml @ 65% solution = 180.555 ml
total = 225 ml out of 500 ml = 45%
It would flow toward the weaker solution. The intent of osmosis is to gain equilibrium, so the 15 percent solution would gain sugar content until, if you allowed the osmosis to go to completion, the two solutions had the same amount of sugar in them. "Going to completion" doesn't necessarily mean 20 percent concentration on both sides. If you were to make a gallon bag out of dialysis membrane, fill it with 15 percent solution and put a stirrer in it, then drop it into a 25,000-gallon reaction vessel full of 25 percent solution with a stirrer in it, you might wind up with 24.9999999999 percent sugar solution in both bags.
You will need more data about all densities (in kg/Litre)and you must be sure of using mass% = (g solute)/(100 g solution)Solve two equations for both X and Y:4*d50*50 = X*d20*20 + Y*d70*70 (based on salt mass balance in diff. sol'n.)4*d50 = X*d20 + Y*d70 (based on solutions mass balance)In which:dm = density of the 'm'% salt solution in kg/Litre)X and Y = volume of the 20% and 70% salt solutions respectively
some liquid volumes are not additive, leading to potentially confusing final solution volumes.
10 gallons..
50 liters
A 3 percent solution is 1.5 times as strong as a 2 percent solution.
yes it is isotonic solution.
32% per yodeladioh
Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300. Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300] 80Q + 9000 - 30Q = 12000 50Q = 3000 Q = 60...........which means (300 - Q) = 240 60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.
Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.
times it together
58.1 ml
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
You will have to assume that the 2 % is a volume fraction, then the volume of copper sulfate in the solution would be 11.5 milliliter(575 ml*(0.02). If it were a weight fraction, then you would have to have more information on the solution density.
It would flow toward the weaker solution. The intent of osmosis is to gain equilibrium, so the 15 percent solution would gain sugar content until, if you allowed the osmosis to go to completion, the two solutions had the same amount of sugar in them. "Going to completion" doesn't necessarily mean 20 percent concentration on both sides. If you were to make a gallon bag out of dialysis membrane, fill it with 15 percent solution and put a stirrer in it, then drop it into a 25,000-gallon reaction vessel full of 25 percent solution with a stirrer in it, you might wind up with 24.9999999999 percent sugar solution in both bags.
When we describe a concentration as a percentage without specifying the type of formula, we imply that the solution is to be made using the weight-in-volume (w/v) method. As with w/w, weight-in-volume is a simple type of formula for describing the preparation of a solution of solid material in a liquid solvent. This method can be used to describe any solution, but is commonly used for simple saline solutions and when the formula weight of the solute is unknown, variable, or irrelevant, which is often the case with complex dyes, enzymes or other proteins. Solutions that require materials from natural sources are often prepared w/v because the molecular formula of the substance is unknown and/or because the substance cannot be described by a single formula. A one percent solution is defined as 1 gram of solute per 100 milliliters final volume. For example, 1 gram of sodium chloride, brought to a final volume of 100 ml with distilled water, is a 1% NaCl solution. To help recall the definition of a 1% solution, remember that one gram is the mass of one milliliter of water. The mass of a solute that is needed in order to make a 1% solution is 1% of the mass of pure water of the desired final volume. Examples of 100% solutions are 1000 grams in 1000 milliliters or 1 gram in 1 milliliter.
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?