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You will need more data about all densities (in kg/Litre)

and you must be sure of using mass% = (g solute)/(100 g solution)

Solve two equations for both X and Y:

  1. 4*d50*50 = X*d20*20 + Y*d70*70 (based on salt mass balance in diff. sol'n.)
  2. 4*d50 = X*d20 + Y*d70 (based on solutions mass balance)

In which:

dm = density of the 'm'% salt solution in kg/Litre)

X and Y = volume of the 20% and 70% salt solutions respectively

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Q: A chemist needs 4 liters of a 50 percent salt solution All she has available is a 20 percent salt solution and a 70 percent salt solution How much of each of the two solutions should she mix to obtain?
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