Three of them.
You can always tell a number is divisible by eight by checking to see if the rightmost three digits are. If they are, then the whole number is. With that in mind then, you can make up all sorts of such numbers by just grabbing some combination that you know is divisible by eight, and tacking additional digits on to the left. For example, we know that 128 is divisible by eight (128 / 8 = 16), so any of these numbers are as well: 89469128 13948128 90173128 The number of digits doesn't matter, so we also know that a ridiculously large number like this one: 25098174509840582437575109283102477568758134024 is divisible by eight, because the last three digits are.
No.First off, 120 is not divisible by 9. (The sum of the digits of 120 is "3"; a number is divisible by nine if and only if the sum of its digits is divisible by nine.) For that matter, it's not divisible by 36 either; since 36 is itself divisible by 9, any number which is not divisible by 9 cannot be divisible by 36.The smallest number that's divisible by 1, 2, 3, 6, 9, 12 and 36 is "36" (it's also divisible by 4, which you left out).
12689 14689 12489
Instead of reading the numbers from left to right (1234) read them from right to left (4321).
14
You can always tell a number is divisible by eight by checking to see if the rightmost three digits are. If they are, then the whole number is. With that in mind then, you can make up all sorts of such numbers by just grabbing some combination that you know is divisible by eight, and tacking additional digits on to the left. For example, we know that 128 is divisible by eight (128 / 8 = 16), so any of these numbers are as well: 89469128 13948128 90173128 The number of digits doesn't matter, so we also know that a ridiculously large number like this one: 25098174509840582437575109283102477568758134024 is divisible by eight, because the last three digits are.
Add up the digits---5+2+7+8 22 which is NOT a multiple of 3 so it is NOT divisible by 3. == Here is a list of the divisibility rules: 2 If the last digit is even, the number is divisible by 2. 3 If the sum of the digits is divisible by 3, the number is also. 4 If the last two digits form a number divisible by 4, the number is also. 5 If the last digit is a 5 or a 0, the number is divisible by 5. 6 If the number is divisible by both 3 and 2, it is also divisible by 6. 7Take the last digit, double it, and subtract it from the rest of the number;if the answer is divisible by 7 (including 0), then the number is also. 8If the last three digits form a number divisible by 8,then so is the whole number. 9 If the sum of the digits is divisible by 9, the number is also. 10 If the number ends in 0, it is divisible by 10. 11 Alternately add and subtract the digits from left to right. (You can think of the first digit as being 'added' to zero.)If the result (including 0) is divisible by 11, the number is also.Example: to see whether 365167484 is divisible by 11, start by subtracting:[0+]3-6+5-1+6-7+4-8+4 = 0; therefore 365167484 is divisible by 11. 12 If the number is divisible by both 3 and 4, it is also divisible by 12. 13Delete the last digit from the number, then subtract 9 times the deleteddigit from the remaining number. If what is left is divisible by 13,then so is the original number
Sum the digits in blocks of three from right to left. If the result is divisible by 27, then the number is divisible by 27
No.First off, 120 is not divisible by 9. (The sum of the digits of 120 is "3"; a number is divisible by nine if and only if the sum of its digits is divisible by nine.) For that matter, it's not divisible by 36 either; since 36 is itself divisible by 9, any number which is not divisible by 9 cannot be divisible by 36.The smallest number that's divisible by 1, 2, 3, 6, 9, 12 and 36 is "36" (it's also divisible by 4, which you left out).
Because any number to left of the last two digits is, by definition a multiple of 100, and as that (100) is of course divisible by 4, then they can be disregarded when checking to see if the whole number id divisible by 4
12689 14689 12489
16682 is not evenly divisible by 6; a remainder of 2 is left.6 is not evenly divisible by 16682; a remainder of 6 is left.The numbers are divisible; the quotient is about 0.000360.
The left side of the vertical rule of a stem-and-leaf plot is the "stem", so the numbers are the "stem," also.
301
The leading digits refers to the first numbers in the typical way from left to right. For instance, for a number like 2837. 258, the leading digits are 2 and 8.
Instead of reading the numbers from left to right (1234) read them from right to left (4321).
I go for 9,876,545,640 Can't say I am certain, though.