6 of them.
4C2 = 4!/(2!*2!) = 4*3/(2*1) = 6
In case of digits or numbers, when we say combination, since the order of the numbers matters, we really need to find the permutations. For example, 12 and 21 are two permutations and not combination. The permutation for 10 digits chosen 5 ways is 10*9*8*7*6, which is 30240. But how many are there in whole like four digit has 24.
There are 8 different combinations.There are 145 permutations that total 14.Not asked, but answered for completeness sake; there are 1296 possible permutations of four dice, making the probability of a sum of 14 being 145 in 1296 or about 0.1119.
2222
6P4 = 6!/(6-4)! = 6 * 5 * 4 * 3 = 360 four letter permutations from 6 different letters.6C4 = 6!/[4!∙(6-4)!] = 15 four letter combinationsfrom 6 different letters.
Assuming that 2356 is a different number to 2365, then: 1st digit can be one of four digits (2356) For each of these 4 first digits, there are 3 of those digits, plus the zero, meaning 4 possible digits for the 2nd digit For each of those first two digits, there is a choice of 3 digits for the 3rd digit For each of those first 3 digits, there is a choice of 2 digits for the 4tj digit. Thus there are 4 x 4 x 3 x 2 = 96 different possible 4 digit numbers that do not stat with 0 FM the digits 02356.
No. It has four digits and each one of these is in a different place. No. It has four digits and each one of these is in a different place. No. It has four digits and each one of these is in a different place. No. It has four digits and each one of these is in a different place.
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.
8264
In case of digits or numbers, when we say combination, since the order of the numbers matters, we really need to find the permutations. For example, 12 and 21 are two permutations and not combination. The permutation for 10 digits chosen 5 ways is 10*9*8*7*6, which is 30240. But how many are there in whole like four digit has 24.
9,999,876 is the greatest seven-digit number using four different digits.
9876 is the largest four digit number you can make if all the digits must be different.
With the constraints you have listed, there are only 6 possible phone numbers:202-1178202-1187202-1718202-1781202-1817202-1871The first four digits are fixed, and there are six possible permutations of three different digits.
120 four letter permutations if you don't allow more than one 'o' in the four letterarrangement.209 four letter permutations if you allow two, three and all four 'o'.1.- Let set A = {t,l,r,m,}, and set B = {o,o,o,o}.2.- From set A, the number of 4 letter permutations is 4P4 = 24.3.- 3 letters from set A give 4P3 = 24, and one 'o' can take 4 different positions in theword. That gives us 24x4 = 96 four letter permutations.4.- In total, 24 + 96 = 120 different four letter permutations.5.- If the other three 'o' are allowed to play, then you have 2 letters from set A thatgive 4P2 = 12 permutations and two 'o' can take 4C2 = 6 position's, giving 12x6 = 72four letter permutations.6.- One letter from set A we have 4P1 = 4, each one can take 4 different positions, therest of the spaces taken by three 'o' gives 4x4 = 16 different permutations.7.- The four 'o' make only one permutation.8.- So now we get 72 + 16 + 1 = 89 more arrangements adding to a total of 89 + 120 = 209 different 4 letter arrangements made from the letters of the word toolroom.[ nCr = n!/((n-r)!∙r!); nPr = n!/(n-r)! ]
There are 104, or 10000 permutations of four 10 sided dice.
There are 8 different combinations.There are 145 permutations that total 14.Not asked, but answered for completeness sake; there are 1296 possible permutations of four dice, making the probability of a sum of 14 being 145 in 1296 or about 0.1119.
If the digits are all different then 18. Otherwise, 192.
8642