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The number of different 3-card hands that can be dealt from a deck of 52 cards is given by the combination formula, which is:

C(52, 3) = 52! / (3! * (52 - 3)!) = 22,100

Therefore, there are 22,100 different 3-card hands that can be dealt from a deck of 52 cards.

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7mo ago
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7y ago

Assuming the 52 cards are all different, the first card can be any of the 52, the second card can be any of the remaining 51, and the third card can be any of the remaining 50, so there are 52x51x50 different three card hands possible.

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12y ago

Assuming 3 cards were drawn:

Each suit has 13 cards. There are 4 suits. For any one suit, there are 13C3 ways of drawing 3 cards. Multiply this by 4.

number of hands = 4 (13C3) = (286)(4) = 1136

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15y ago

tierce is the answer tierce is the answer

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3y ago

132600

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Q: How many possible hands are there for getting 3 cards of the same suit?
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How many possible hands are there for only getting 4 cards that make a straight?

2,560


How many possible hands are there for getting 4 cards of the same suit?

A suit contains 13 cards of the same kind. 4 cards may be choosen out of 13 in 13C4 (715) ways. There are 4 suits. Therefore, the number of possible hands for getting 4 cards of the same suit is 4 x 13C4 = 4 x 715 = 2,860.


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If the cards are all different then there are 13C7 = 1716 different hands.


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How many possible hands are there for getting 3 Cards of the same suit and 2 random cards?

13 x 12 x 11 x 49 x 48 13 x 12 x 11 because there are 13 possible cards for any given suit, then 12 more of the same suit, then 11 more for the same suit. At this point, you have 49 cards left, then 48. So there are 4,036,032 possible hands like that.


How many possible hands can be dealt from a standard deck of cards in Texas hold em?

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How many possible hands are there for getting 4 cards in the same suit with the other cards in any other random suit?

The odds of getting 4 cards in any particular suit (for example, hearts) would be:1/4*1/4*1/4*1/4=1/256.The odds of getting 4 cards of the same suit (any suit) would be 4x greater:1/256*4=1/64Because it doesn't matter what the last card is, the probability is 1/64.


How many 5 card poker hands consisting of three 8's and two cards that are not 8's are possible in a deck?

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How many poker hands can be made that are all face cards?

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How many 5 card poker hands contain only red cards?

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How many 3 card hands are possible from a standard deck of 52 cards?

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Consider a standard deck of 52 cards how many different four cars hands have no red cards?

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