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We know that there are two possibilities for a coin to land on, heads or tails, and there are six possibilities to roll, 1 to 6, so for ever one of the possibilities for the coin there are six possibilities for the die so we do 6x2 and get 12. To prove this I will write it all out t is tails and h is heads:

T1, T2, T3, T4, T5, T6, H1, H2, H3, H4, H5, H6. If you count them you get 12.

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Q: How many possible outcomes of tossing a coin and rolling a 6-sided number cube can you show step by step how you came to the solution?
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Related questions

How many possible outcomes of tossing a coin and rolling a 6-sided number cube?

There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.


Multiplication to find the number of possible outcomes for tossing a dime and rolling a die?

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There are 26 = 64 possible outcomes.


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What are the outcomes for rolling a die and and tossing a coin?

The sample space for rolling a die is [1, 2, 3, 4, 5, 6] and the sample space for tossing a coin is [heads, tails].


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The total number is 6*6*2 = 72 outcomes.


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