We know that there are two possibilities for a coin to land on, heads or tails, and there are six possibilities to roll, 1 to 6, so for ever one of the possibilities for the coin there are six possibilities for the die so we do 6x2 and get 12. To prove this I will write it all out t is tails and h is heads:
T1, T2, T3, T4, T5, T6, H1, H2, H3, H4, H5, H6. If you count them you get 12.
1/2 * 1/6
The cube has 6 possible outcomes.The coin has 2 possible outcomes.There are 6 x 2 = 12 possible outcomes for a trialthat involves both the cube and the coin.
The total number is 6*6*2 = 72 outcomes.
The probability of an event is the number of favourable outcomes divided by the total number of possible outcomes. What is the total number of possible outcomes of tossing a number cube? 6 How many outcomes are favourable to the event of getting a five? 1 So the prob is 1/6 or 0.16667
480
There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.
1/2 * 1/6
There are 25 or 32 possible outcomes can you get by tossing 5 coins.
There are 23 = 8 possible outcomes.
There are 26 = 64 possible outcomes.
it would be 2*2*6 which would equal 24
The cube has 6 possible outcomes.The coin has 2 possible outcomes.There are 6 x 2 = 12 possible outcomes for a trialthat involves both the cube and the coin.
The sample space for rolling a die is [1, 2, 3, 4, 5, 6] and the sample space for tossing a coin is [heads, tails].
20
The total number is 6*6*2 = 72 outcomes.
purple
The probability of an event is the number of favourable outcomes divided by the total number of possible outcomes. What is the total number of possible outcomes of tossing a number cube? 6 How many outcomes are favourable to the event of getting a five? 1 So the prob is 1/6 or 0.16667