There are 23 = 8 possible outcomes.
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You find the sample space by enumerating all of the possible outcomes. The sample space for three coins is [TTT, TTH, THT, THH, HTT, HTH, HHT, HHH].
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
Only if you're counting order. If you call a head then a tail different from a tail and then a head then there are 8 outcomes from the coins; otherwise there are only 4. And clearly a number cube can have anywhere from 1 to 6 outcomes, depending on whether the same number appears multiple times.
When we toss a coin getting head or tail have equal probability of 50% - that is, out of the two possible outcomes getting the specified one becomes 1/2 probability. When we toss three coins, the probability of getting all the coins showing tails is given by (1/2) * (1/2) * (1/2) equal to 1/8 or 12.5 % chance. Alikban