You find the sample space by enumerating all of the possible outcomes. The sample space for three coins is [TTT, TTH, THT, THH, HTT, HTH, HHT, HHH].
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
Only if you're counting order. If you call a head then a tail different from a tail and then a head then there are 8 outcomes from the coins; otherwise there are only 4. And clearly a number cube can have anywhere from 1 to 6 outcomes, depending on whether the same number appears multiple times.
When we toss a coin getting head or tail have equal probability of 50% - that is, out of the two possible outcomes getting the specified one becomes 1/2 probability. When we toss three coins, the probability of getting all the coins showing tails is given by (1/2) * (1/2) * (1/2) equal to 1/8 or 12.5 % chance. Alikban
three heads two head, one tails one heads, two tails three tails
You find the sample space by enumerating all of the possible outcomes. The sample space for three coins is [TTT, TTH, THT, THH, HTT, HTH, HHT, HHH].
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
There are eight (8).
Eight of them.
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
There are three possibilities, Heads, Tails and stand on edge
7/8
9, you just have to multiply for problems like this
Only if you're counting order. If you call a head then a tail different from a tail and then a head then there are 8 outcomes from the coins; otherwise there are only 4. And clearly a number cube can have anywhere from 1 to 6 outcomes, depending on whether the same number appears multiple times.
When we toss a coin getting head or tail have equal probability of 50% - that is, out of the two possible outcomes getting the specified one becomes 1/2 probability. When we toss three coins, the probability of getting all the coins showing tails is given by (1/2) * (1/2) * (1/2) equal to 1/8 or 12.5 % chance. Alikban
20