6 (worth 12 units,) added to the 4 units gives 10 units worth 24.
(This is the sort of problem we used to get at Primary school in the 1950's. It's probably University Entrance standard nowadays!)
Let x = pounds at 10/lb and Y = 30 pounds at 4/lb and Z = 30 +x = total pounds at 6/lb; then 10X + 4Y = 6Z solve for x 10x + 120 = 180 + 6x x = 15 pounds
LET X = pounds of chocolate. Then total weight is X + 3 and 5.95X + 2.95(3) = 3.95 (X+3) 5.95X + 8.85 = 3.95X +11.85 2X = 3 X = 1.5 pounds
100
52/15=the #
cost of buying 200= 37 pounds Divide then into packs of 20, gives you 10 packs Selling 10 packs for 5 punds gives you 50 pounds you've gained 50-37=13 pounds
let x = pounds of coffee at 2$/pound 2.00X + 1.20 (3) = 1.76 (X+3) 2.00X + 3.60 = 1.76X + 5.28 .24X = 1.68 X = 7 pounds
80pounds
70000000
230
Let x = pounds at 10/lb and Y = 30 pounds at 4/lb and Z = 30 +x = total pounds at 6/lb; then 10X + 4Y = 6Z solve for x 10x + 120 = 180 + 6x x = 15 pounds
in a 42 cup coffee maker how many pounds of coffee do you need
more than 100,000 pounds
My coffee table weighs 25 pounds.
16 POUNDS about
50 lbs
Approximately 6 2/3 cups, or 1.4 pounds ground coffee.
It depends on kinds of coffee, and packing as well.