Red non-face cards are:
A, 2, 3, 4, 5, 6, 7, 8, 9, 10 of hearts
A, 2, 3, 4, 5, 6, 7, 8, 9, 10 of diamonds
20 in total
There are 9 non-diamond face cards in a standard 52 card deck.
The probability is 11/13.
It is 1: the event is a certainty if you keep drawing cards. The probability that the first three cards drawn are non-face cards, which is quite a different event from that described in the question, is approx 0.4471
There are 12 picture cards and 38 non-picture cards in a deck of 52 cards. The probability that you do not pick a picture card is therefore 38/52 = 19/26.
Prob(At least one ace in ten cards out of 52) = 1 - Prob(No aces in ten cards out of 52) When you start there are 48 non-ace cards out of 52, At the next draw, there are 47 non-ace cards out of 51, and so on = 1 - (48/52)*(47/51)* ... *(39/43) = 1 - 0.41 = 0.59
Well there are 12 face cards (4- jacks, 4-queens, 4-kings) so there are 40 non-face cards.
There are 9 non-diamond face cards in a standard 52 card deck.
There are 9 non-diamond face cards in a standard 52 card deck.
It is approx 0.41
The probability is 11/13.
In a standard deck of cards it is one with a value ranging from 2 to 10 (inclusive).
Well there are 12 face cards (4- jacks, 4-queens, 4-kings) so there are 40 non-face cards.
2 face cards and 3 non-face cards = (12C2)(40C3) = (66)(9880) =652,080 3 face cards and 2 non-face cards = (12C3)(40C2) = (220)(780)=171,600 4 face cards and 1 non-face cards = (12C4)(40C1) = (495)(40)=19,800 5 face cards = 12C5 =792 Adding: 844,272 hands
It can be argued that a 'kind' of card is merely a particular grouping of the cards. Using this definition, there could be (omitting Jokers)... Red/Black - 2 Face/Non-face - 2 Club/Diamond/Heart/Spade - 4 1s,2s,3s,...Ks,As - 13 There could be additional possible groupings...Male/Female/Neuter, odd/even, divisible by 3/4/etc., cards with a face value <6... Then, we could combine some of these to create new groupings... Red Face/Red Non-face/Black Face/Black Non-face - 4 Color+suit is redundant, since suit is a subset of color Color+value (e.g. Black 1s, Red 1s,...) yields 26 categories Suit+Face/Non-face (e.g. Heart Face cards) - 8 Face/Non-face + Value is redundant Suit+value - 52 However, based on the vague definition of 'kinds of cards', there are too many possible solutions to solve this one.
It is 1: the event is a certainty if you keep drawing cards. The probability that the first three cards drawn are non-face cards, which is quite a different event from that described in the question, is approx 0.4471
You must be using a non traditional deck. I have never heard of the woodcutter
The outcome will depend on the random variable that you choose to define over the event space. It could be the face value and suit of the card, it could be the face value, it could be the suit, it could be red or black, it could be an honour or non-honour, odd or even, etc.