The probability is 11/13.
There are 9 non-diamond face cards in a standard 52 card deck.
It is 18/52 = 9/26
Red non-face cards are: A, 2, 3, 4, 5, 6, 7, 8, 9, 10 of hearts A, 2, 3, 4, 5, 6, 7, 8, 9, 10 of diamonds 20 in total
The probability of drawing two cards that are a 2 when the first card is an Ace is zero, because a two is not an Ace. They are mutually exclusive events. If this is not clear, consider the probability of rolling a seven on one roll of one six sided die. That probability is also zero - it will not happen.
The probability is 11/13.
It is approx 0.41
2 face cards and 3 non-face cards = (12C2)(40C3) = (66)(9880) =652,080 3 face cards and 2 non-face cards = (12C3)(40C2) = (220)(780)=171,600 4 face cards and 1 non-face cards = (12C4)(40C1) = (495)(40)=19,800 5 face cards = 12C5 =792 Adding: 844,272 hands
Well there are 12 face cards (4- jacks, 4-queens, 4-kings) so there are 40 non-face cards.
There are 9 non-diamond face cards in a standard 52 card deck.
It is 18/52 = 9/26
There are 9 non-diamond face cards in a standard 52 card deck.
It can be argued that a 'kind' of card is merely a particular grouping of the cards. Using this definition, there could be (omitting Jokers)... Red/Black - 2 Face/Non-face - 2 Club/Diamond/Heart/Spade - 4 1s,2s,3s,...Ks,As - 13 There could be additional possible groupings...Male/Female/Neuter, odd/even, divisible by 3/4/etc., cards with a face value <6... Then, we could combine some of these to create new groupings... Red Face/Red Non-face/Black Face/Black Non-face - 4 Color+suit is redundant, since suit is a subset of color Color+value (e.g. Black 1s, Red 1s,...) yields 26 categories Suit+Face/Non-face (e.g. Heart Face cards) - 8 Face/Non-face + Value is redundant Suit+value - 52 However, based on the vague definition of 'kinds of cards', there are too many possible solutions to solve this one.
Red non-face cards are: A, 2, 3, 4, 5, 6, 7, 8, 9, 10 of hearts A, 2, 3, 4, 5, 6, 7, 8, 9, 10 of diamonds 20 in total
Face cards in a regular set of playing cards consist of Jack, Queen, King, and Ace. With these 4 face cards occurring in all 4 suits (hearts, diamonds, clubs, and spades), that gives 16 total face cards. If we draw 4 cards without putting them back, the probabilities are calculated on each draw as (number of face cards remaining)/(total number of cards remaining) 1st draw: 16/52 = 0.307692308 2nd draw: 15/51 = 0.294117647 3rd draw: 14/50 = .28 4th draw: 13/49 = 0.265306122 These are the individual probabilities of each step independent of each other. To calculate the probability when depending on the success of the previous step, we simply multiply each step's probabilities together. Probability of drawing N face cards in a row: 1: (16/52) = 0.307692308 2: (16/52)*(15/51) = 0.0904977376 3: (16/52)*(15/51)*(14/50) = 0.0253393665 4: (16/52)*(15/51)*(14/50)*(13/49) = 0.00672268908 This translates to approximately a 7 in 1000 chance of drawing 4 face cards in a row out of a deck of 52 cards!
Probability is 1/2 or 50%. Explanation: A normal deck of cards has 52 cards, consisting of four different suits each having 13 cards. Two suits are red, and two are black. This means the deck has 26 red cards. The probability that a red card will be drawn out of the 52 cards is 26 / 52 = 1/2.
In a standard deck of cards it is one with a value ranging from 2 to 10 (inclusive).