Ignoring air resistance . . .
H = 1/2 G t2
t = sqrt(2H/G) = sqrt(2 x 363 / 32.2) = 4.75 seconds (rounded)
There are 12 inches in a foot and 60 seconds in an inch:(5 minutes / 1 foot) * (60 seconds / 1 minute) * (1 foot / 12 inches) = 25 seconds per inch(Notice that the minute and foot units cancel out leaving seconds per inch.)
Using Pythagoras' theorem the the foot of the ladder should be 12 feet away from the base of the building.
Just over 1 second. Gravity moves objects here on Earth at 32 ft per second squared. At the end of the first second it will fall 32 of the 36 ft.
48
50000 sq foot
39 seconds
it will take about 30 seconds to 1 whole minute.
A pebble is dropped from the top of a 144-foot building. The height of the pebble h after t seconds is given by the equation h=−16t2+144 . How long after the pebble is dropped will it hit the ground?Interpretationa) Which variable represents the height of the pebble, and in what units?b) Which variable represents the time in the air, and in what units?c) What equation relates the height of the object to its time in the air?d) What type of equation is this?e) What are you asked to determine?
1.5 seconds (if dropped on earth).
Assuming that air resistance can be ignored, s = ut + 0.5gt2 where s is the distance travelled = 324 feet, u is the initial velocity = 0 ft/sec, t is the time (in seconds), and g is the acceleration due to gravity = 32 ft/sec2 Therefore 324 = 0.5*16*t2 so that t2 = 20.25 and so t = 4.5 seconds.
3.7 seconds neglecting air resistance. 220 foot clearance at tide.
No a water balloon dropped from 1 foot
56
Periferal nerve
There are 12 inches in a foot and 60 seconds in an inch:(5 minutes / 1 foot) * (60 seconds / 1 minute) * (1 foot / 12 inches) = 25 seconds per inch(Notice that the minute and foot units cancel out leaving seconds per inch.)
Length of line: 90/cos(22) = 97 feet rounded to nearest the foot
They fall to the ground at the same time, regardless how much they weigh.