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Assuming that air resistance can be ignored,

s = ut + 0.5gt2

where

s is the distance travelled = 324 feet,

u is the initial velocity = 0 ft/sec,

t is the time (in seconds), and

g is the acceleration due to gravity = 32 ft/sec2

Therefore 324 = 0.5*16*t2 so that t2 = 20.25 and so t = 4.5 seconds.

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Q: How long will it take ball that is dropped from a 324 foot tall building to hit the ground?
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