You have (10+26) = 36 characters all together.
The first character can be any one of 36. For each one . . .
The second character can be any one of the remaining 35. For each one . . .
The third character can be any one of the remaining 34. For each one . . .
.
.
.
The seventh character can be any one of the remaining 30.
The total number of possibilities is (36 x 35 x 34 x 33 x 32 x 31 x 30) = 42.0723 billion. (rounded)
9x8x7x6x5x4x3x2x1 or 9! which equals 362880 possible combinations if no digits are repeated
The number of 4 digit codes, using different digits, is 10*9*8*7 = 5040. However, computer passwords can, usually, have repeated digits and, if that is allowed, you can have 104 = 10000 codes.
There are 26 possible letters and 10 possible numbers. The number of license plates possible is then 26*26*10*10*10*10 = 6760000.
You can make 916,132,832 different five-character passwords if the code can be a mixture of letters and digits in any order and is case sensitive.
3!*3!=36For example, if you want to use the alphabets a,b,c and three digits 1,2,3 you can make the following 36 different passwords (3 letters followed by 3 digits)abc123abc132abc231abc213abc312abc321acb123acb132acb231acb213acb312acb321bca123bca132bca231bca213bca312bca321bac123bac132bac231bac213bac312bac321cab123cab132cab231cab213cab312cab321cba123cba132cab231cab213cab312cab321
263 X 103 = 17576000
9x8x7x6x5x4x3x2x1 or 9! which equals 362880 possible combinations if no digits are repeated
The number of 4 digit codes, using different digits, is 10*9*8*7 = 5040. However, computer passwords can, usually, have repeated digits and, if that is allowed, you can have 104 = 10000 codes.
There are 26 possible letters and 10 possible numbers. The number of license plates possible is then 26*26*10*10*10*10 = 6760000.
5040
You can make 916,132,832 different five-character passwords if the code can be a mixture of letters and digits in any order and is case sensitive.
3!*3!=36For example, if you want to use the alphabets a,b,c and three digits 1,2,3 you can make the following 36 different passwords (3 letters followed by 3 digits)abc123abc132abc231abc213abc312abc321acb123acb132acb231acb213acb312acb321bca123bca132bca231bca213bca312bca321bac123bac132bac231bac213bac312bac321cab123cab132cab231cab213cab312cab321cba123cba132cab231cab213cab312cab321
2600
If repeated digits are allowed, then the largest 12-digit number is 999,999,999,999 .If repeated digits are not allowed, then the largest 12-digit number is 989,898,989,898 .If the same digit can't be used more than once, then the largest possible number has only10 digits. The number is 9,876,543,210 .
9876
It is possible to create a 3-digit number, without repeated digits so the probability is 1.
0000-9999 (10x10x10x10 or 104) = 10,000 possible combinations allowing for repeated digits. If you are not able to repeat digits then it's 10 x 9 x 8 x 7 or 5,040 possible combinations without repeated digits.