It will have 35 sides
Providing that it is a regular 35-agon then its interior angles add up to 5940 degrees and each interior angle is 5940/35 = 169.'714285' degrees recurring decimal '714285'
It is: (5940+360)/180 = 35 sides
A polygon with an angle sum of 5940o would have 1,069,198 sides.The equation to find the angle sum of a polygon is (n - 2) / 180We can substitute the figures we know and solve as for an ordinary linear equation by rearranging to isolate the n as our variable.(n - 2 ) / 180 = 5940(n - 2 ) = 5940 * 180n - 2 = 1,069,200n = 1,069,200 - 2= 1,069,198So a polygon that has an angle sum of 5940o would have 1,069,198 sides.
35 sides
It has 35 sides.
It will have 35 sides and can be described as a 35-agon
Sum of interior angles is (2n-4) right angles There are 66 right angles in 5940 degrees So (2n - 4) = 66 2n = 70 n = 35
Each interior angle can have any value in the range (0, 360) degrees, excluding 180 degrees. The only restriction is that the interior angles sum to 5940 degrees.
The interior angles add up to 5940 degrees
Interior angles: 5940
5940.
It's often easier to calculate the external angle and subtract this result from 180 to obtain the interior angle. External angle of a 35-gon = 360/35 = 10.2857° Interior angle of a 35-gon = 180 - 10.2857 = 169.7143° The formal way is to use the formula that the Sum of the interior angles = 2n - 4 right angles.....where n is the number of sides. Sum of interior angles = [(2 x 35) - 4] x 90 = 66 x 90 = 5940 Then each interior angle = 5940 / 35 = 169.7143°