A polygon with an angle sum of 5940o would have 1,069,198 sides.
The equation to find the angle sum of a polygon is (n - 2) / 180
We can substitute the figures we know and solve as for an ordinary linear equation by rearranging to isolate the n as our variable.
(n - 2 ) / 180 = 5940
(n - 2 ) = 5940 * 180
n - 2 = 1,069,200
n = 1,069,200 - 2
= 1,069,198
So a polygon that has an angle sum of 5940o would have 1,069,198 sides.
It is: (5940+360)/180 = 35 sides
35 sides
The interior angles add up to 5940 degrees
It has 35 sides.
It will have 35 sides and can be described as a 35-agon
Sum of interior angles is (2n-4) right angles There are 66 right angles in 5940 degrees So (2n - 4) = 66 2n = 70 n = 35
Providing that it is a regular 35-agon then its interior angles add up to 5940 degrees and each interior angle is 5940/35 = 169.'714285' degrees recurring decimal '714285'
Each interior angle can have any value in the range (0, 360) degrees, excluding 180 degrees. The only restriction is that the interior angles sum to 5940 degrees.
It will have 35 sides
5940 degrees
Interior angles: 5940
The sum of the angles of ANY n-sided polygon is (2n - 4) right angles. In your example n = 35 so (70 - 4) x 90 ie 5940 degrees