A polygon with an angle sum of 5940o would have 1,069,198 sides.
The equation to find the angle sum of a polygon is (n - 2) / 180
We can substitute the figures we know and solve as for an ordinary linear equation by rearranging to isolate the n as our variable.
(n - 2 ) / 180 = 5940
(n - 2 ) = 5940 * 180
n - 2 = 1,069,200
n = 1,069,200 - 2
= 1,069,198
So a polygon that has an angle sum of 5940o would have 1,069,198 sides.
It is: (5940+360)/180 = 35 sides
35 sides
The interior angles add up to 5940 degrees
It has 35 sides.
It will have 35 sides and can be described as a 35-agon
Sum of interior angles is (2n-4) right angles There are 66 right angles in 5940 degrees So (2n - 4) = 66 2n = 70 n = 35
To find the number of sides ( n ) of a polygon given its interior angle, we use the formula for the interior angle of a regular polygon: [ \text{Interior angle} = \frac{(n-2) \times 180}{n} ] Setting this equal to 5940, we can rearrange and solve for ( n ). However, since 5940 is an unusually high angle, it suggests that the polygon is not regular or has been misinterpreted, as typical interior angles of polygons do not exceed 180 degrees. Thus, please check the angle value again, as standard polygons do not have an interior angle of 5940 degrees.
Providing that it is a regular 35-agon then its interior angles add up to 5940 degrees and each interior angle is 5940/35 = 169.'714285' degrees recurring decimal '714285'
Each interior angle can have any value in the range (0, 360) degrees, excluding 180 degrees. The only restriction is that the interior angles sum to 5940 degrees.
It will have 35 sides
5940 degrees
Interior angles: 5940