Sum_interior_angles = (number_of_sides - 2) x 180o
→ number_of_sides = sum_of_interior_angles ÷ 180o + 2
= 1800o ÷ 180o + 2
= 12
It will have (1800+360)/180 = 12 sides
If the interior angles add up to 1800 degrees then it will have 12 sides
12 sides
2800 degrees * * * * * No. The interior angles of a polygon with n sides is (n-2)*180 degrees. Here, n = 12 so the answer is 1800 degrees. A polygon whose interior angles added to 2800 degrees would have 17 5/9 sides! Since a fractional number of sides is impossible, so is such a polygon.
A polygon with a sum of interior angles equal to 1800 degrees has 12 sides, making it a dodecagon. This can be determined using the formula for the sum of interior angles of a polygon, which is ((n - 2) \times 180) degrees, where (n) is the number of sides. Setting this equal to 1800 and solving for (n) yields (n = 12).
12
The interior angles of a 12 sided polygon add up to 1800 degrees
1800 degrees. (Number of sides - 2) x 180 = (12 -2) x 180 =10 x 180 = 1800
1800= (n-2)180, 1800= 180n-360, 1800+360= 2160, 2160 divided by 180 = 12
The interior angles add up to 1800 degrees
The formula is: (12-2)*180 = 1800 degrees
The sum of the interior angle measures=(the number of sides-2) times 180. So 1440=(n-2)180. 180n-360=1440 180n=1800 n=10 The polygon has 10 sides.