It wouldn't exist if the angles added up to 172o: the minimum sum for the angles of a polygon is that of a triangle, 180o - all the polygons with more sides are multiples of this, namely 4 sides => sum is 360o, 5 sides => sum is 540o, etc.
If you mean:
How many sides would a polygon have if all the angles were 172 degrees?
then the answer is 45 sides.
For all polygons:
For a regular polygon:
Interior angle = 1720 => exterior_angle = 8o
=> number_of_sides = 360o / 8o = 45.
E
A regular polygon with exterior angles of 30 degrees has: 360/30 = 12 sides
If all of its exterior angles are 90 degrees then it will have 4 sides
It is a quadrilateral polygon that has 4 sides and 4 interior angles that add up to 360 degrees.
Exterior angles = 360 degrees Interior angles = 2340 degrees
360 degrees
Any polygon can have two interior angles of 12 degrees. No polygon can have all its interior angles of 12 degrees.
2800 degrees * * * * * No. The interior angles of a polygon with n sides is (n-2)*180 degrees. Here, n = 12 so the answer is 1800 degrees. A polygon whose interior angles added to 2800 degrees would have 17 5/9 sides! Since a fractional number of sides is impossible, so is such a polygon.
If each interior angles is 179 degrees, then the polygon has 360 sides
A regular polygon with exterior angles of 30 degrees has: 360/30 = 12 sides
By 900 degrees as for example a triangle has 3 sides that add up to 180 degrees then if 5 sides are added to it then it then is an 8 sided octagon with interior angles that add up to 1080 degrees
35 sides
15 sides
That's true if the interior angles are 108 degrees, but a regular polygon cannot have exterior angles of 108 degrees.
If all of its exterior angles are 90 degrees then it will have 4 sides
If all of the interior angles of the polygon add up to 180 degrees, then the polygon is a triangle.
The polygon would be a heptagon.So, the polygon would have 7 sides.
A polygon whose interior angles are 2880 degrees has 18 sides.