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That's true if the interior angles are 108 degrees, but a regular polygon cannot have exterior angles of 108 degrees.

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It has five sides.

Q: If the exterior angle of a regular polygon is 108 degrees how many sides does the polygon have?

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Each exterior angle measures 36 degrees

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If its a regular 9 sided polygon then the exterior angles are 40 degrees.

The measure of 1 exterior angle of a regular 8-sided polygon is equivalent to 45 degrees. Hope I helped! :)

If those are exterior angles, the exterior angles of any polygon add up to 360. That would be 18 sides.

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Each exterior angle of a regular polygon with n sides is 360/n degrees. Each interior angle of a regular polygon is 180 - Exterior angle. A direct formula for the interior angle is 180*(n-2)/n degrees.

No.

If each exterior angle is 9 degrees then it is a regular 40 sided polygon.

Each exterior angle is 15 degrees

360 ________________________________________________ Sum of Interior Angles of a Polygon = 180 (n-2) Sum of Exterior Angles of a Polygon = 360 The sum of an angle and an exterior angle of a regular polygon is 360

Providing that it's a regular polygon then each exterior angle will measure 12 degrees.

If it's a regular polygon then each exterior angle measures 36 degrees

Each exterior angle measures 36 degrees

Each exterior angle is 72 degrees

Each exterior angle measures 15 degrees

The sum of all exterior angles of a polygon is 360 degrees. In a regular polygon, all of the exterior angle are equal, so there must be 360/72=5 sides of the polygon, which makes it a pentagon.

Interior angle = 120 degrees Exterior angle = 60 degrees