There are 4 significant figures in 6.741.
It's a number of digits which you have to take in count when you have to round a number (physical value such as speed, acceleration and so on). e.g. if you have the number 0.0000067 the signifigant figures are 67; zeros don't matter, unless they are between two actual numbers like in 405000 the signifigant figures are 405
Two - the trailing zeros are just placeholders.
7: 0.00003050=.0000305 The two zeroes on each end can be taken off because taking them off will NOT change the value of the number. * * * * * Not so. None of the zeros before the 3 are significant - they are only place holders. Conversely, the zero after the 5 IS significant. Its presence indicates a precision that is ten times greater. So, the significant digits are 3050 - 4 of them.
4 significant figures.Zeros are significant if they are between two non-zero numbers, or if they are "trailing" zeros in a number with a decimal point.Eg.0.000047 = 2 significant figures4.7000 = 5 significant figures
The equation for the reaction is 4 Na + O2 -> 2 Na2O. This shows that, for complete reaction, one mole of oxygen is required for each four gram atomic masses of sodium. The gram atomic mass of sodium is 22.9898; therefore, 46 grams of sodium constitutes 2.00 moles of sodium, to more than the justified number of significant digits. The gram molecular mass of diatomic oxygen is 31.9988; therefore 160 grams of oxygen constitutes 5.000 moles of diatomic oxygen, to more than the justified number of significant digits. This is well over the minimum amount of oxygen required for complete reaction of all the sodium present. Each two gram atomic masses of sodium produces one gram formula mass of sodium oxide; therefore, the number of gram formula masses of sodium oxide produced is 1.00, to at least the justified number of significant digits.
8(6741)3= 8(7654)3 the digits between 8,3 are 4. 6(7)4=6(5)4 so the answer is four (8,3&6,4)
same number of significant digits
There's no set amount. The answer varies with each number.
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
It's a number of digits which you have to take in count when you have to round a number (physical value such as speed, acceleration and so on). e.g. if you have the number 0.0000067 the signifigant figures are 67; zeros don't matter, unless they are between two actual numbers like in 405000 the signifigant figures are 405
the digits of a number that are used to express it to the required degree of accuracy, starting from the first nonzero digit.
There is one significant figure (which I assume you are referring to).However there are 7 digits involved, of which all are significant. Each digit is important and special in its own right. None should be singled out as being different, as that is Digitist.* * * * *Leaving aside the political correctness of the anti-digitism, the number of significant digits depends on the context. In the above example, if it is known that the number is not 3,999,999 nor 4,000,001 then all seven digits are significant. If it is known that the number is 4,000 thousand (not 3,999 thousand or 4,001 thousand) then there are 4 sig digs.
Two - the trailing zeros are just placeholders.
Count the significant digits in each of the factors, and take the smallest of them.
3 sig figs.
28
1