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It may or may not exist. If the matrix of coefficients is singular then there is no solution.
A reaction doesn't exist; the solution contain ions of calcium, iodine, sodium and nitrate.
There is only one type of solution if there are two linear equations. and that is the point of intersection listed in (x,y) form.
Yes, they can exist.
Roman numeral system.
x+y=0 2x+2y=0 This homogeneous system has infinitely many non-trivial solutions. If you are looking for exactly one non-trivial solution, no such system exists. the system may or may not have non trivial solution. if number of variables equal to number of equations and given matrix is non singular then non trivial solution does not exist
A homogeneous system of eqs: Ax=0 will always be consistent, since x=0 is always a possible solution. However, if det(A)=0 then there will be infinite solutions, as |A|=0 implies that either no solutions or infinitely many exist, and it is impossible for no solutions to exist to Ax=0. If det(A) is non 0, then x=0 is the only solution, as |A| is not equal to 0 implies a unique solution only!(in this case x=0). Hope this helps!
Hydroxyl ion exist in solution but it is not a solution.
Ferric ions exist in solutions.
Can exist but need not.
Just think this.....is the solar system did NOT exist then we would not exist.
Any difference exist. A simple solution may be a diluted solution.
Tyndall effect doesn't exist in a sugar solution.
positrons (the anti-particle of electrons); protons; metal ions in a solution (for example, Na+); the dopant ions (for example, B+) in a semiconductor junction. Please note that a system with only one type of isolated charges, positive or negative, is highly unstable. Unless the net charge in the system is zero, the system will be very unhappy. For example, in an atom, protons are chemically stable because of surrounding electrons. In an aqueous solution, metal ions co-exist with an equal number of negative ions. =============================
It absorbs them from the water, where they exist in solution.
solidity
Yes, there is a unique solution.