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The number of digits in the square root of a number depends on the number. If it is a square number, the square root will have a finite number of digits. If the number is not a square number then the square root will be an irrational number with an infinite, non-repeating decimal representation. In both cases, the number of digits before the decimal point, in the square root of x will be the rounded value of 1+0.5*log10(x)
The square root is the number which is times by itself, to get the square number.
Sometimes the square root of a positive number can be irrational, as in the square root of 2 (which is a non-perfect square number), but sometimes it is a rational number, as in the square root of 25 (which is a perfect square number).
the square root of a number is the number that is multiplied by itself to get that number, for example the square root of 9 is 3
Pi is an irrational number and has an infinite number of digits after the decimal point. So does its square root.
3 is the square root of 9. 9 is a square number. 9 is the square root of 81. 81 is a square number.
Nothing. You cannot have a square root of a negative number. The square root of negative one is called i, but i is an imaginary number. It does not exist and does not follow the properties of real numbers. (For example, if a and b are positive, then the square root of a times the square root of b is the square root of ab. But the square root of -7 is not the square root of 7 times i.)
It's not a square if it has no root. If a number is a square then, by definition, it MUST have a square root. If it did not it would not be a square.
The number 3 is the square root of the number 9 !
No - a natural number is a whole number. Therefore, the square root of 49 is a natural number, but the square root of 50 is not.
No it is not.
The square root of 51 is an irrational number and it is about 7.14128429