The number of digits in the square root of a number depends on the number.
If it is a square number, the square root will have a finite number of digits. If the number is not a square number then the square root will be an irrational number with an infinite, non-repeating decimal representation.
In both cases, the number of digits before the decimal point, in the square root of x will be the rounded value of 1+0.5*log10(x)
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There are infinitely many of them. They include square root of (4.41) square root of (4.42) square root of (4.43) square root of (4.44) square root of (4.45) square root of (5.3) square root of (5.762) square root of (6) square root of (6.1) square root of (6.2)
because it is the square root of ten it has a lot of numbers for accuracy
7.071 and 7.072 [ square root of 49 ] and [ square root of 51 ]
That's the same as the square root of positive 340, times i. Many calculators can't calculate the square root of negative numbers, since they are not set up to calculate with complex numbers, but you can simply calculate the square root of the equivalent positive number, then add "i" to the result.
Yes, but they are imaginary - but are needed in many mathematical calculations. The square root of negative 1 is indicated as the letter "i".