First letter in code can be any of 5, second can be any of remaining 4 and so on. 5 x 4 x 3 x 2 = 120
It is 720.
The number of permutations of the letter SUM is 3 factorial, or 6. Since none of those letters are repeated, the issue of repetition is not a factor. Perhaps the questioner meant to use a different word. If so, please restate the question.
This would be 26 x 26 x 10 x 10 = 67,600. Provided repetition is allowed.
4*4*4 = 64 ways.
10 (x 6 if no repetition is allowed but abc is not regarded as the same as acb), 125 if it is. ABC/ABD/ABE/ACD/ACE/ADE/BCD/BCE/BDE/CDE
How many three-letter "words" can be made from 10 letters "FGHIJKLMNO" if repetition of letters are not allowed
many i believe 8 or so??
There are 676,000 ways to make the license plates.
It is 720.
If repetition is allowed the formula would be 4x4x4 = 64 codes. If you must chose a different letter each time (no repetition) the formula would be 4x3x2 = 24 codes.
The number of permutations of the letter SUM is 3 factorial, or 6. Since none of those letters are repeated, the issue of repetition is not a factor. Perhaps the questioner meant to use a different word. If so, please restate the question.
Assuming no repetition, 12 x 11 x 10.... x 4 x 3 x 2. If repetition is allowed, 1212
Alliteration is the repetition of the same consonant sounds and assonance is the repetition of the same vowel sounds.
That repetition would involve an onomatopoeia.
It is (5/26)4 = 625/456,976 = 0.00137 approx.
uncopyrightable
This would be 26 x 26 x 10 x 10 = 67,600. Provided repetition is allowed.