8.
48 of them if digits may not be repeated. 100 if they can.
99999
If you don't repeat, 20. If you do, 58.
To form a three-digit number using the digits 1-7, we can choose any of the 7 digits for each of the three places (hundreds, tens, and units). Therefore, the total number of 3-digit combinations can be calculated as (7 \times 7 \times 7), which equals 343. Thus, there are 343 different three-digit numbers that can be formed using the digits 1-7.
There are 3,265,920 numbers that can be formed using all the digits. The answer to the question will depend on which one of these.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
There are 60480 numbers.
There are 4^6 = 4096 such numbers.
If the digits are all different then 18. Otherwise, 192.
depends on your answer
15 of them.
27