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What is the largest possible product of three 3 digit numbers all of whose digits are different?
Forming three three digit numbers that use the numbers 1-9 without repeating, the highest product possible is 611,721,516. This is formed from the numbers 941, 852, and 763.
How many 4-digit numbers can be formed by the digits 2 4 6?
81 As there are no limits stated then you can have a number comprising a repeated single digit (such as 2222), two pairs of numbers (e.g. 2244) or three different numbers (such as 2462). The first digit can be one of any of the 3 numbers. The second digit can be one of any of the three numbers, as can the third digit and also the fourth. Then you can have 3 x 3 x 3 x 3 = 81 different 4-digit numbers using the three given numbers.
How many different three digit numbers can be formed from the digits 0 through 9 if the first digit must be odd and the last digit must be even?
5 x 10 x 5 = 250 different numbers, assuming there is no limit to each digits' use.
What is the smallest three-digit number divisible by the first three prime numbers and the first three composite numbers?
The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.
How many three digits numbers are there between 99 and 3000?
Well honey, the numbers between 99 and 3000 are inclusive, so you gotta count 'em all. To find out how many three-digit numbers there are, you subtract the first three-digit number (100) from the last three-digit number (999) and add 1, giving you a grand total of 900 three-digit numbers. So, buckle up and start counting, darling!
