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If I understand the question correctly, Mario can have five toppings on his Pizza, and he can choose any five from a menu of eleven possible toppings, correct? Yeah, this one's easy. He has eleven different choices for the first topping, ten for the second, and so on. So, to calculate how many different combinations this is, we just multiply:

11 x 10 x 9 x 8 x 7

However, the order of 5 the toppings doesn't matter. For example, a pepperoni, sausage, green pepper, olive, and onion pizza is exactly the same as a sausage, pepperoni, onion, olive, and green pepper pizza, so you don't want to count it more than once. The number of ways you can arrange 5 toppings is 5X4X3X2X1. So the final answer is (11 X 10 X 9 X 8 X 7) / (5 X 4 X 3 X 2 X 1) = 462

This is referred to as "11 choose 5" denoted 11C5. It is the operation used to determine lottery probabilities.

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Q: How many times can Mario choose a 5 topping pizza from a menu of 11 toppings if each topping can be used once?
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