2 from 5 = (5 x 4 x 3 x 2)/(3x2)x (2) = 5 x 4/2 =10
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
6 Is how many different combinations there are
There are 30 different combinations if the order in which the books were chosen counts, so a set of book A and book B is considered different from a set of book B and book A. There are 15 different combinations if it does not matter in which order the books were chosen, so a set of book A and book B is considered the same as a set of book B and book A.
There are 10 x 9 x 8 ways to select 3 numbers from 10 in order (permutations of 3 numbers from 10), but as want the number of combinations, the order doesn't matter, so need to divide by the number of ways 3 numbers can be ordered which is 3 x 2 x 1. Thus: combinations(3 from 10) = (10 x 9 x 8)/(3 x 2 x 1) = 120. There are formulae for the number of permutations and combinations of r items chosen from a set of n items: Permutations: nPr = n!/(n-r)! Combinations: nCr = n!/(n-r)!r! Where n! means "n factorial" which is the product of n with all numbers less than it to 1, ie n! = n x (n-1) x ... x 2 x 1 The combinations nCr is also written as a vector with n over r, as in (nr), but it is difficult to show the n exactly over the r as it should be (with the characters available) so I use the nCr format which is found on scientific calculators.
You can choose 5 different hats and for each of them 4 different sunglasses can be chosen, giving 5 x 4 = 20 different combinations.
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
It is: 15C7 = 6435 combinations
The number of 4 different book combinations you can choose from 6 books is;6C4 =6!/[4!(6-4)!] =15 combinations of 4 different books.
6 Is how many different combinations there are
There are 30 different combinations if the order in which the books were chosen counts, so a set of book A and book B is considered different from a set of book B and book A. There are 15 different combinations if it does not matter in which order the books were chosen, so a set of book A and book B is considered the same as a set of book B and book A.
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
The Terracotta Warriors Site was built by Ancient Chinese slaves and also by the King's workers ordered by him and chosen by him.
The Terracotta Warriors Site was built by Ancient Chinese slaves and also by the King's workers ordered by him and chosen by him.
There are 10 x 9 x 8 ways to select 3 numbers from 10 in order (permutations of 3 numbers from 10), but as want the number of combinations, the order doesn't matter, so need to divide by the number of ways 3 numbers can be ordered which is 3 x 2 x 1. Thus: combinations(3 from 10) = (10 x 9 x 8)/(3 x 2 x 1) = 120. There are formulae for the number of permutations and combinations of r items chosen from a set of n items: Permutations: nPr = n!/(n-r)! Combinations: nCr = n!/(n-r)!r! Where n! means "n factorial" which is the product of n with all numbers less than it to 1, ie n! = n x (n-1) x ... x 2 x 1 The combinations nCr is also written as a vector with n over r, as in (nr), but it is difficult to show the n exactly over the r as it should be (with the characters available) so I use the nCr format which is found on scientific calculators.
You can choose 5 different hats and for each of them 4 different sunglasses can be chosen, giving 5 x 4 = 20 different combinations.
plz help asap
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.