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If you know one point on a graph and you also know the slope of the graph, you can use the point-slope equation to create the y-intercept form of the line. Doing this will allow you to plug in values for x or y to get any point on the graph. For example, say that the slope of the line is 2 and a point on the line is (3,2). The point-slope form is y - y1 = m(x - x1). Plug in (3,2) and the slope to get y - 2 = 2(x - 3). That simplifies to y = 2x - 4. I want to see what y-value falls on the line at x = 5, so I plug that in. I get y = 6. That means that there is also the point (5,6) on the graph.
The slope is the rise of the line divided by the run of the line. For example if the slope says 3/2, from the point you are on, you move to the right two times and then move up 3 spots
If the point is x=a, y=b, the line is (y-b)=slope times (x-a).Or, slope=(y-b)/(x-a)So (y+1/2)=1/2 (x-1/3)Another answer:-Point: (1/3, -1/2)Slope: 1/2Equation: y - -1/2 = 1/2(x -1/3) => y = 1/2x -2/3In its general form: 3x -6y -4 = 0
x and y form an ordered pair representing the coordinates of every point on the line defined by the equation. x is the horizontal distance of a point from the origin, which is the point where the axes cross, while y is the vertical distance of the point from the origin.
You use the point slop formula to find the Y intercept. (Y value of point) minus (x value of point times slope) = y intercept. Your line is then slope times x plus the Y-intercept, and you can graph it as you would any other line. If you need more help, message me. Hope this helps. ~Skularach This is simply asking, "Hey, how do I find the Y intercept in the slope-intercept formula so that I can graph the bleeding thing when I only know a point on the line (x,y) and the slope? The slope-intercept equation is y=mx+b where x and y are coordinates on the line, m=the slope and b=the Y intercept (that is, where the line intersects the vertical axis on the Cartesian coordinate plane, ans X always is equal to 0). So, let's try an example: Let's say the point you know (x, y) is (1,2) and the slope is 3 So, SUBSTITUTE THESE VALUES IN THE EQUATION Y=MX+B 2=(3)(1)+B So, solve for B: B = 2 - 3 = -1 So (0, -1) is your Y intercept. On a sheet of graph paper go down one square below the ordinate or centre or (0,0) and draw a dot. Slope=Rise/Run = 3/1 So, starting with the dot you just drew, go one square to the right and up three squares and draw another dot at (2,1)----As you see, you could have just gone ahead and drawn the dot at (2,1) on the graph to begin with, but I wanted to illustrate how slope comes in. Now, simply draw a straight line between (0,-1) and (2,1) on the page and extend the line in both direction to the edges of the paper, putting arrows at both ends. Behold, your line!
As Anand Mehta said, you could use partial derivatives. Or differentials, which is quite similar. It works like this: assuming that you have a surface area, "z", defined in terms of "x" and "y". At some specific point, the slope might be, for example:z = 0.5 delta x + 0.3 delta y This means that for any increment (delta) in x, by a certain amount, z would increase by 0.5 times that amount; similarly, for any delta y (increment in y), z would increase by 0.3 times that amount.
You take the x and times it by the y and divide 4
Slope and some times size
5
I could be for one person and not for another.
Well a variable in a number in a linear equation is basically the variable divided by a number. So if you have x over 10, it is basically x times 1/10. You can solve by having either another equation and use either point slope or y=mx+b.
y = 1/2x y = 1/2 times x to the negative 1 ( 1/2 x^-1) The slope is from differential calculus: slope = dy/dx = -1/2 times x to the negative 2 = -1/2x^2