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ReneTo solve this equation, we need a point where the perpendicular line and the y=2x-3 line will meet. So let's say the equation is still y=2x-3 and a point on this line is (2,1). The slope of the perpendicular line will always be the slope of y=2x-3 (the slope = 2) times it's reciprocal which should also be negative (-1/2). Now we know that the slope for the line perpendicular to y=2x-3 is -1/2. To find the equation of the perpendicular line, we need to use the point-slope formula
[y - y1 = m(x - x1)]. To solve this formula we need the slope of the perpendicular line ( -1/2) and the point (2,1). y-1 = -1/2(x-2) becomes y = -1/2x+2 is the equation for the line that is perpendicular to y=2x-3. Hope this helps :)
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