Twenty times.
Without repeats there are 4 × 3 = 12 possible 2 digit numbers. With repeats there are 4 × 4 = 16 possible 2 digit numbers.
With repeats: 4×4 = 16; Without repeats: 4×3 = 12.
Well if repeats are allowed, then unlimited. If you can repeat the numbers then the list would go on forever.
how many times gerater is the underlined digit 5 in 365,486,201 than the digit 5
Assuming leading zeros are not permitted, then: If repeats are not allowed there are 30 possible numbers. If repeats are allowed there are 60 possible numbers.
120
Without repeats there are 4 × 3 = 12 possible 2 digit numbers. With repeats there are 4 × 4 = 16 possible 2 digit numbers.
With repeats: 4×4 = 16; Without repeats: 4×3 = 12.
Since 1100 divided by 9 is 122.222... , 9 can go into 1100 122 times.
Well if repeats are allowed, then unlimited. If you can repeat the numbers then the list would go on forever.
1.1936 times.
if the repetition is allowed the there is 6*6*6 possible ways = 216
55 times.
Exactly 44 times
how many times gerater is the underlined digit 5 in 365,486,201 than the digit 5
Assuming leading zeros are not permitted, then: If repeats are not allowed there are 30 possible numbers. If repeats are allowed there are 60 possible numbers.
36.67 times, or 36 times with a remainder of 20.