Without repeats there are 4 × 3 = 12 possible 2 digit numbers.
With repeats there are 4 × 4 = 16 possible 2 digit numbers.
100000 - including numbers with leading 0s
24 different numbers.
how make the answer im don/now
192, including ones containing repeat digits.
60 different numbers can be formed from the digits {1, 2, 3, 4, 5} is no repeats are allowed Any of the first digits can be chosen for the first digit, leaving 4 for the next and 3 for the final digit. Thus there are 5 × 4 × 3 = 60 different possible such permutations of 3 digits from the 5.
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
10,000
36
100000 - including numbers with leading 0s
24 different numbers.
5 x 10 x 5 = 250 different numbers, assuming there is no limit to each digits' use.
how make the answer im don/now
27 three digit numbers from the digits 3, 5, 7 including repetitions.
192, including ones containing repeat digits.
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
60 different numbers can be formed from the digits {1, 2, 3, 4, 5} is no repeats are allowed Any of the first digits can be chosen for the first digit, leaving 4 for the next and 3 for the final digit. Thus there are 5 × 4 × 3 = 60 different possible such permutations of 3 digits from the 5.
500