The missing number is 5. They're the first five prime numbers.
Two possible answers spring immediately to mind. First, this sequence appears to be a list of the first five prime numbers; in this case, the next number in the sequence would be 13. Second, the intervals between these numbers comprise the sequence "1 2 2 4", in which the nth number equals the product of the (n-1)th and (n-2)th numbers. Based on this, the next number in the given sequence would be 11 + (4*2) = 19.
Assuming that you can use each number multiple times, 3125, because there are five options for the first number, five for the second, and so on to reach five. Then, five times five times five times five times five, or five to the fifth power, equals 3125. Were you only able to use each number once, the answer would be 120 based on the same principle. There would be five options for the first number, four remaining options for the second, three for the third, two for the fourth, and then one for the fifth. Then, as with the first, five times four times three times two (times one, but that really isn't necessary) results in 120.
The mode is the number that shows up the most in a sequence of numbers. Ex. 5,3,2,8,9,10,10,4,5,5. Since five show up the most( 3 TIMES) THEN THIS MAKES IT THE MODE
The first five prime numbers are 2, 3, 5, 7, 11. The sum of these five numbers is 28.
The sum of the first five whole numbers is 10.
Assuming the first five numbers is meant to refer, not to the first five real numbers but to the first five positive integers, the answer is 1*2*3*4*5 = 120
The first five abundant numbers are 12, 18, 20, 24, and 30.
the first positive even numbers are 2,4,6,8,10
2,1,0 is th sequence of its terms
The first five whole numbers are: 01234. The first five natural numbers are: 12345.
The first five prime numbers above 10 are: 11, 13, 17, 19, 23.
The first five two-digit prime numbers are 11, 13, 17, 19, and 23.
The five on the left is ten times the five on the right.
5. If the mean ("average") of the first five numbers is 11, that means they add up to 55 (5 times their mean value of 11). Similarly, all six numbers have to add up to 60 (6 times their mean value of 10). The final number is the difference between these sums (60 - 55), or 5.
The first five prime numbers are 2,3,5,7,11. The sum of the first five prime numbers is 28.The sum is: 2+3+5+7+11 = 28
You would use a zero 11 times in writing the numbers 1 to 100 once - so doing it five times gives you 55 zeros.
Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.
The first five prime numbers are 2, 3, 5, 7, and 11. I don't know what you mean by "of 28".
Because they are the first five numbers divisible only by one and themselves.
The first five prime numbers are 2, 3, 5, 7, 11. The product of these five numbers is equal to 2 x 3 x 5 x 7 x 11 = 2310.
9 and 10
38 and 190