You can find the prime factorization of 130: 130 = 2*5*13 Therefore the answer is 1. Or you can skip a step. Just divide 130 by 2. You get 65, which is an odd number. Therefore there is only 1 factor of 2 in the factorization of 130.
32 has one prime factor: 232 has only one prime factor: 2
31 is a prime number. Its only prime factor is 31.
To change numbers into index notation, express the number as a product of its prime factors. For each prime factor, write it in the form of a base raised to an exponent, where the exponent indicates how many times that prime factor is used. For example, the number 60 can be factored into primes as (2^2 \times 3^1 \times 5^1). This notation clearly shows the composition of the number using its prime factors.
2 is the only prime factor of 16.
The only prime factor of 16 is two.
The only prime factor of 25 is 5.
Two
There is only 1 prime factor of 56 and it is 7.
34 has one distinct prime factor.
Since there are infinitely many prime numbers, there can be no such number.
The exponent tells how many times the base is used as a factor.