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Q: How many times does the prime factor 2 appear in the factorization of 130?

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The prime factorization of 81 is 3 * 3 * 3 * 3 or 3^4 The prime factorization for 81 is 3 times 3 times 3 times 3

The prime factorization of 20 is, 2 squared times 5( because two is prime' 2 times 2 is 4, times 5(which is prime) equals 20)

. For example, the factorization of 120 is 23 x 3 x 5, meaning 2 is a factor three times and 3 and 5 are each a factor one time for a total of five prime factors.

no, 6 is not a prime number.

42, (2 times 3 times 7).

Related questions

Each prime factor will appear an even number of times.

The number 32 cannot appear as a prime factor!

the prime factorization is 5 to the second power times 2 times 3

4 to the second power times four

In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.

The prime factorization of 129= 43 times 3

The prime factorization is 2 to the 2nd power times 3 times 7.

The factor tree would be hard to show so here is the prime factorization.41 times 5

You can just divide 130 by 2 and get 65, which is odd so it doesn't have 2 as a factor. Therefore the answer is 1.Answer 1You need to find the prime factorization of 130. 130 = 2*5*13Therefore the answer is 1.

The prime factorization of 81 is 3 * 3 * 3 * 3 or 3^4 The prime factorization for 81 is 3 times 3 times 3 times 3

If your asking what is the prime factorization of 14: 2 times 7

The number 2 appears four times in the prime factorization of 400: 2 x 2 x 2 x 2 x 5 x 5

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