0
How many total possibilities are there if you know the first number but not the second two but you know that all three numbers are different?
Wiki User
∙ 11y ago
360
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
What are all of the possible 4 digit numeric combinations using 3-6?
If it could be 3333, then your answer would be four to the fourth power, which is 256. Can prove that as: The first number has 4 possibilities, and the second has 4 possibilities, so if each of the possibilities in the first number has four possibilities for the second number, the number of possibilities of the two is 16, and that can continue if the third number as four possibilities, so you can have 64 combination of those three numbers, and of those 64 numbers each of them could have 4 different numbers after them, so you have 256 combinations. If it could not repeat digits it would be 4x3x2x1 which is 24. can prove that as: 1.3456 2.3465 3.3546 4.3564 5.3645 6.3654 7.4356 8.4365 9.4536 10.4563 11.3635 12.4653 13.5346 14.5364 15.5436 16.5463 17.5643 18.5634 19.6345 20.6354 21.6435 22.6453 23.6534 24.6543
If A standard combination lock has 60 numbers on its face from 0 to 59 a combination consits of three numbers and numbers can be repeated what is the total number of possible combinations?
There are 60 possible numbers for the first number, A, in the combination (1,2,3,...,59,60).For each of outcome of A, there are 60 outcomes for the second number, B, giving a two digit combination 60x60=360 possibilities.For each of these 360 outcomes, there are 60 outcomes for the third number, C, making the number of possible combinations 360x60=21600.Or 60 possibilities x 60 possibilities x 60 possibilities = 21,600 possibilities.
How many 3 digit numbers contain no repetition of digits?
Let's consider the following distribution: __ __ __ Each space represents one number. The first number can be anything from 0-9 (10 possibilities). The second number, after choosing the first number, can only have 9 possibilities. The reasoning behind this is if we choose the same number as the first, then there is a repetition. So we can't use that same number again. The third number can only have 8 possibilities by the same logic as for the second digit. Therefore there can be 10*9*8 = 720 3-digit numbers with no repetitions of digits.
Are these numbers the sAME 1267343 1276343?
No. The first consists of the number 1267343 whereas the second set consists of a different number.
How many different ways can you arrange 7 letter words?
The best way to think of this is how many options there are for each letter. There are 7 possibilities for the first letter. Then there are 6 possibilities (out of the remaining letters) for the second latter. Then 5 possibilities for the next, and so on. The total number of possibilities will be 7x6x5x4x3x2x1, which equals 5,040. So there are 5,040 different ways to arrange 7 letter words.
You are a five digit number your digits increase in size from the left Each digit is different your first and fifth digits are square numbers your first and fourth digits are cubed numbers your 2nd?
There are a lot of possibilities. The second digit can be 2 through 6, the third digit can be 3 through 7 as long as it is larger than the second digit. What we have so far: 1 _ _ 89
What are all the possible combinations of 4 using only 3 variables?
I'm sorry what i was meaning what r all the 4 number combinations that can be made with 3 numbers. Ie. 1111,1112,1113,1121,1122,1123,1131,1132,1133, etc. In that case, we can think of it this way For the first one, there is 3 possibilities, 1, 2, 3. For each one of them, the second one also have three possibilities, 1, 2, 3. Since there is three for every different first number, there is 9 possibilities for just the first two. Hope you see the pattern, for all 4, it would be 3 x 3 x 3 x 3 which is 81 different possibilities.
The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers?
= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
How do you find the LCM of 2 numbers if one number is prime?
If the second number is a multiple of the prime number, than the LCM is the second number. If the second number is not a multiple of the prime number, then the two numbers are relatively prime, and the LCM is the product of the two numbers.
Double numbers on bass tabs?
If the numbers are different, they indicate that you slide from fret (first number) to fret (second number). Tabs tend to vary depending on who writes them, though, which can be confusing.
How many 3 digit numbers can be formed with digits 1 2 3 4 5 if no digit occurs twice within the same number?
60. If any of the numbers 1-5 can be in the first position, there are 5 possibilities for that spot. Since whichever number is in the first position can't be used again, that leaves 4 numbers possible for the second spot. Again, since whatever is in the middle can't be used for the last number, that leaves 3 possibilities. 5X4X3= 60
How many three digit even numbers are there?
3 digit positive even numbers is: 9 x 10 x 5 = 450 because in the first spot you can have 1-9 (9 possibilities) , the second spot 0-9 (10 possibilities), and the third you can have 0, 2, 4, 6, 8 (5 possibilities).
