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If A standard combination lock has 60 numbers on its face from 0 to 59 a combination consits of three numbers and numbers can be repeated what is the total number of possible combinations?
Wiki User
∙ 14y ago
There are 60 possible numbers for the first number, A, in the combination (1,2,3,...,59,60).
For each of outcome of A, there are 60 outcomes for the second number, B, giving a two digit combination 60x60=360 possibilities.
For each of these 360 outcomes, there are 60 outcomes for the third number, C, making the number of possible combinations 360x60=21600.
Or 60 possibilities x 60 possibilities x 60 possibilities = 21,600 possibilities.
Wiki User
∙ 14y ago
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