A regular hexagon can be divided into 6 equilateral triangles by drawing diagonals between opposite vertices, if that helps.
That would depend on which hexagon and what triangles. A small hexagon might not have room for any large triangles. A large hexagon will have room fro many small triangles.If you have a regular hexagon and connect the vertices you will have drawn six equilateral triangles
you can split a regular hexagon into 6 triangles
Six equilateral triangles are found in a regular 6 sided hexagon
hexagon
Equilateral
equilateral
6
If you mean the area of the regular hexagon, then the answer is yes.
If all the vertices of the regular hexagon are joined to the centre of the hexagon, 6 equilateral triangles are created: the area of the hexagon is 6 times the area of one of these triangles. If the length of the side of the hexagon is m, then the length of each of the sides of these triangles is also m. Using Pythagoras the height of these triangles can be found to be m x sqrt(3)/2. Thus the area of the hexagon = 6 x area triangle = 6 x (m x m x sqrt(3)/2) / 2 = (3/2) sqrt(3) m2 ~= 2.6 x square of length_of_side
There are 5 triangles in an heptagon
equilateral.