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If all the vertices of the regular hexagon are joined to the centre of the hexagon, 6 equilateral triangles are created: the area of the hexagon is 6 times the area of one of these triangles.
If the length of the side of the hexagon is m, then the length of each of the sides of these triangles is also m. Using Pythagoras the height of these triangles can be found to be m x sqrt(3)/2.
Thus the area of the hexagon
= 6 x area triangle
= 6 x (m x m x sqrt(3)/2) / 2
= (3/2) sqrt(3) m2
~= 2.6 x square of length_of_side
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What is the area of hexagon?
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
What is the area of a regular hexagon with 24 inch perimeter?
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
What is the area of a regular hexagon with side lengths of 10 units?
The area of a regular hexagon with side lengths of 10 units is about 259.8 units2
Can a regular hexagon be found by breaking the hexagon into six congruent triangles and then taking the sum of their areas?
If you mean the area of the regular hexagon, then the answer is yes.
How do you calculate an area of a hexagon?
If it is a regular hexagon then make 6 triangles then find the area of one then multiply by 6.
