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Q: How many unique values are possible using a single binary digit?

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Answer: 2The values are 0 or 1.

It would be 2 raised to the power 32: 4,294,967,296.

0 & 1

1. A single bit can represent two different values, 0 and 1. Then simply take the largest of those two possible values, 1, and that's your answer.

A binary variable.

please tell me answer of this question. Suppose you are building an N node binary search tree with the values 1...N. how many structurally different binary trees is there that store those values? write a recursive function that, gives the number of distinct values, computes the number of structurally unique binary search trees that store those values. For example, countTrees(4) should return 14, since there are 14 structurally unique binary search trees that store 1,2,3 and 4. The base case us easy, and the recursion is short but dense. your code should not construct any actual trees; it's just a counting problem.

Binary-valued quantities can be 0 or 1, true or false, right or wrong. There are only 2 possible values.

And what is your question?

Since a binary digit has only two possible values, each digit bears less information than in decimal, where each digit can have ten different values.

The binary values is 10110101.

Binary image (i think)

4 and 6

0111 0110

Binary- 01100111 Decimal Value- 103

A binary tree is simply a tree in which each node can have at most two children. A binary search tree is a binary tree in which the nodes are assigned values, with the following restrictions ; -No duplicate values. -The left subtree of a node can only have values less than the node -The right subtree of a node can only have values greater than the node and recursively defined; -The left subtree of a node is a binary search tree. -The right subtree of a node is a binary search tree.

A binary variable.

It is 1111.

a general rule for binary is that the number of alternatives = 2 raised to the # of bits power. Two to the seventh power is 128

the answer of course is Unique Values

Decimal (more formally, binary coded decimal) values store numeric information as digits encoded using the four bit binary equivalents: 0 (0000) to 9 (1001). That means a single byte can hold values between 0 and 99. But simply using the same byte to hold a binary value will yield values between 0 and 255 (or –128 and +127).

I'm not entirely sure what you're asking.In one sense, "binary number" means a quantity that can take on only two possible values. "True" or "False," for example. "On" or "off." "1" or "0."You can, however, represent other values using a "binary" system. Computers store ordinary numbers like "42" in a binary format. In that case, you'd have something like "0010 1010".

There are four kinds of relations in ordered pairs: one to one (each x value is unique and has a unique y value associated with it) one to many (each x value has multiple possible y values) many to one (each y value has multiple possible x values) many to many (x and y values can be repeated and are not unique) See the related link for more helpful information.

Any base that is itself a power of 2 can be used to notate binary values. That is, base-4, base-8 (octal), base-16 (hexadecimal), base-32, and so on. Binary is a base-2 counting system such that each digit represents one of two possible values (0 or 1). When we combine bits we double the number of possible values with each additional bit. Thus 2 bits can represent up to 4 possible values, 3 bits gives us 8 possible values and 4 bits gives us 16 possible values, and so on. We normally deal with bits in groups of 4 because 2 groups of 4 gives us an 8-bit byte which is the norm for most systems. Thus we can reduce an 8-bit binary value from 8 binary digits to just 2 hexadecimal digits, thus giving us a convenient method of notating binary values with fewer digits and a trivial conversion. Octal notation isn't used as much as hexadecimal notation, but if we wanted to use a 9-bit byte rather than an 8-bit byte (which is not an uncommon activity), octal notation is more convenient than hexadecimal because the 9-bit values can be treated as being exactly 3 groups of 3 bits.

The four fundamental operation have no intrinsic value. As the name suggests, they are operators. In fact, they are binary operators, which means that they take two values as input and their output is a single value. That value will depend on the inputs.

24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...

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