a general rule for binary is that the number of alternatives = 2 raised to the # of bits power.
Two to the seventh power is 128
2 raised to the 8th power, or "2^8", or 256.
Using 4 bits the signed range of numbers is -8 to 7. When working with signed numbers one bit is the sign bit, thus with 4 bits this leaves 3 bits for the value. With 3 bits there are 8 possible values, which when using 2s complement have ranges: for non-negative numbers these are 0 to 7; for negative numbers these are -1 to -8. Thus the range for signed 4 bit numbers is -8 to 7.
24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.
To represent 63 values, you need at least 6 bits, as 2^6 = 64, which can accommodate all 63 values. However, if you're specifically using 8 bits per value, then you would use 8 bits for each of those 63 values, resulting in a total of 63 x 8 = 504 bits.
2 raised to the 8th power, or "2^8", or 256.
To determine how many bits are required to store a specific value, you need to know the range of values that must be represented. The formula to calculate the number of bits (n) needed is ( n = \lceil \log_2(V) \rceil ), where ( V ) is the number of unique values. For example, to store integers from 0 to 255 (256 values), you would need 8 bits, since ( \log_2(256) = 8 ).
If the key is one byte long, then there are 8 bits that can be positive or negative. With all permutations of 8 bits, that leaves 2^8 (two to the eighth power) possibilities, which is only 256 total unique values.
In an 8-bit binary system, the total range of decimal values that can be represented depends on whether the representation is signed or unsigned. For unsigned 8 bits, the range is from 0 to 255. For signed 8 bits, using two's complement, the range is from -128 to 127.
16 bits. Java char values (and Java String values) use Unicode.
Eight bits to the octet. The values are 0-255.
Four bytes can store (2^{32}) different values, since each byte consists of 8 bits and 4 bytes equal 32 bits. This means that the total number of unique combinations is (2^{32} = 4,294,967,296). This range includes values from 0 to (4,294,967,295) for unsigned integers, or from (-2,147,483,648) to (2,147,483,647) for signed integers.
16 bits per block
16 bits per block
Using 5 bits, a total of (2^5) different numbers can be represented. This equals 32, allowing for values ranging from 0 to 31 in unsigned binary representation. If signed representation is used (e.g., two's complement), the range would be from -16 to 15, still totaling 32 distinct values.
4.1 bit for 2,2 bits for 4,3 bits for 8,4 bits for 16.