It would be 2 raised to the power 32: 4,294,967,296.
1. A single bit can represent two different values, 0 and 1. Then simply take the largest of those two possible values, 1, and that's your answer.
a general rule for binary is that the number of alternatives = 2 raised to the # of bits power. Two to the seventh power is 128
A binary variable.
24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...
Answer: 2The values are 0 or 1.
It would be 2 raised to the power 32: 4,294,967,296.
1. A single bit can represent two different values, 0 and 1. Then simply take the largest of those two possible values, 1, and that's your answer.
0 & 1
A binary variable.
please tell me answer of this question. Suppose you are building an N node binary search tree with the values 1...N. how many structurally different binary trees is there that store those values? write a recursive function that, gives the number of distinct values, computes the number of structurally unique binary search trees that store those values. For example, countTrees(4) should return 14, since there are 14 structurally unique binary search trees that store 1,2,3 and 4. The base case us easy, and the recursion is short but dense. your code should not construct any actual trees; it's just a counting problem.
Binary-valued quantities can be 0 or 1, true or false, right or wrong. There are only 2 possible values.
Since a binary digit has only two possible values, each digit bears less information than in decimal, where each digit can have ten different values.
Binary image (i think)
4 and 6
The binary values is 10110101.
Decimal (more formally, binary coded decimal) values store numeric information as digits encoded using the four bit binary equivalents: 0 (0000) to 9 (1001). That means a single byte can hold values between 0 and 99. But simply using the same byte to hold a binary value will yield values between 0 and 255 (or –128 and +127).