The first card can be selected out of 52 cards, second from 51 cards, and the third from 50 cards. You may be tempted to give the answer as 52x51x50. But recognize that if you select
1 spade, 5 heart, 8 club, that is the same as
5 heart, 8 club, 5 heart
the order does not matter
So we need to find not nPr but nCr = 52C3 = (52!)/((49!)x(3!)) = (50 x 51 x 52)/6
which is 22100 ways
If you select 45 cards without replacement from a regular deck of playing cards, the probability is 1. For a single randomly selected card, the probability is 2/13.
The answer depends on the numbers on the cards in the bag!
There are 2 red queens, assuming a randomly shuffled deck the chances of any one card being selected is 1 in 52, therefore the chance of either of the red queens being selected is 2 in 52. This is normally shown as 1 in 26.
There are 4 suits in a deck of cards; each suit has a probability of being selected of 1/4. So, probability of a diamond is 1/4 or 0.25.
52 cards divided by four kings.
Example: SELECT * FROM Employees would result in all records for all columns (such as Name, Age, Pay, etc.) being returned.
If you select 45 cards without replacement from a regular deck of playing cards, the probability is 1. For a single randomly selected card, the probability is 2/13.
10
The probability of drawing three diamonds from a standard deck of 52 cards is (13 in 52) times (12 in 51) times (11 in 50), or 1716 in 132600, or about 0.01294.
The answer depends on the numbers on the cards in the bag!
There are 2 red queens, assuming a randomly shuffled deck the chances of any one card being selected is 1 in 52, therefore the chance of either of the red queens being selected is 2 in 52. This is normally shown as 1 in 26.
Sainsbury's, WHsmith or online. (only at selected stores)
The probability, if the cards are not replaced, is 2,535,000/6,497,400 = 0.3902 approx.
There are 4 suits in a deck of cards; each suit has a probability of being selected of 1/4. So, probability of a diamond is 1/4 or 0.25.
52 cards divided by four kings.
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