What is the probability of getting 2 Red suits cards and 2 black suit cards selected randomly from a deck of 52?

Answer 1

Oh, dude, you're talking about a standard deck of 52 cards, right? So, like, there are 26 red cards and 26 black cards in there. If you're picking 4 cards randomly, the probability of getting 2 red and 2 black suits would be calculated by like, dividing the number of ways you can choose 2 red and 2 black cards by the total number of ways to choose 4 cards from 52. It's like a math problem, but with cards, man.

Answer 2

To calculate the probability of selecting 2 red suits and 2 black suits from a standard deck of 52 cards, you first determine the total number of ways to choose 4 cards from 52, which is 52 choose 4 (denoted as C(52,4)). Then, you calculate the number of ways to choose 2 red suits from 26 red cards (26 choose 2) and 2 black suits from 26 black cards (26 choose 2). Finally, you divide the number of favorable outcomes (choosing 2 red and 2 black) by the total number of outcomes (choosing any 4 cards from the deck) to get the probability.

Answer 3

Well, honey, there are 26 red cards and 26 black cards in a standard deck of 52 cards. So, the probability of getting 2 red suits and 2 black suits when you randomly pick 4 cards is just a fancy way of saying you have a 100% chance of getting what you want. It's like asking if Betty White is a national treasure – the answer is obvious!

Answer 4

The probability, if the cards are not replaced, is 2,535,000/6,497,400 = 0.3902 approx.