10
20C2 = 190
The answer is 6C4 = 6*5/(2*1) = 15
36 x 35/2 ie 630
309*308/2 = 47586
2
20, without replacing the first book chosen. 25 with replacing it.
there are like 2 or 3 in the whole game.
2 ways. no 1.Dont worry about gameshark get Action Replay.No 2. type in a code (I dont know what it is) to get 999 rare candies (when you use one you still have 999 so its the same as unlimeted)
There are 26 red cards and 26 black cards. 3 red cards can be chosen in 26C3 ways 2 black cards can be chosen in 26C2 ways The required answer is 26C3 X 26C2 ways. Answer: 1067742 S Suneja
28 gift bags, 3 chocolate candies, and 2 peppermint candies
There are 20 candies of each of the five colors. The probability that when you select 2 candies at random exactly one of the candies will be orange is: P(exactly one turns out orange out of 2) = 2∙(20/100)∙(80/99) = 0.323232... P ≈ 32%
4 choices for the first letter 3 choices for the second, once the first has been chosen 2 choices for the third, once the first and the second have been chosen 1 for the last So it's 4x3x2x1 = 24