20C2 = 190
6,375,600
53,130 ways.
Either 5040 or 210, depending on a whether order is important. Keep reading.Four slots. First slot: 10 people to choose from 2nd slot: 9 people left (1 is already chosen) 3rd: 8 4th: 710*9*8*7=5040, assuming, of course, the people are chosen randomly and no one person can be on the committee twice.But then we need to adjust this figure because there will be some duplication, since if Ben, George, Sue, and Jill are chosen for example, there are different ways that they can be chosen and all four of these same people are still on the committee. This is much like when Lotto balls are draw - you don't really care what order the balls are drawn as long as you match them up. So the number of ways that 4 people can be arranged in 4 positions is 4! = 4 x 3 x 2 x 1 = 24. So dividing 5040 by 24 will give you the number of possible committee selections, assuming that it doesn't matter which order they are chosen.
2,850
There are 4845 ways to choose 4 people out of 20 20 choose 4 = 20! / (4!16!)
It is: 15C7 = 6435 combinations
There are 11880 ways.
6,375,600
36 x 35/2 ie 630
There are 9*8*7 = 504 ways.
27!
To determine the number of ways to elect a president and a secretary treasurer from 12 members, we consider that the president can be chosen in 12 ways. Once the president is chosen, there are 11 remaining members eligible for the role of secretary treasurer. Therefore, the total number of different ways to fill these two offices is (12 \times 11 = 132).
10
*facepalms* "Can you please repeat the question?"
class race ethnicity
class race ethnicity
125